karmachaser
I did not quite understand the solution. im not understanding why we have to assume exactly 1 liter as the initial volume. I setup this problem the exact same way with the proper algebraic equation, but for my initial volume I assumed 10 liters to make the math simple, and got very wonky answers so took too long AND didn't get the right answer.
sure I can just try to remember to use 1 liter as the initial volume as a filler, but why?
Because the question asks for a
fraction, not an actual number of liters.
When you are solving for a fraction, the total volume is just a scaling factor. Whether you start with 1 liter, 10 liters, or 100 liters, everything scales proportionally and cancels out.
Using 1 liter simply removes unnecessary scaling and keeps the algebra clean.