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# M05-29

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Intern
Joined: 01 Sep 2016
Posts: 12

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15 Oct 2016, 17:51
I think this is a high-quality question and I agree with explanation.
Intern
Joined: 22 Jun 2016
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21 Oct 2016, 12:24
Bunuel,

B is proved wrong by taking p=0. Can we also prove it wrong by taking p as negative? For instance if p is -11 then 2p/11 is -2. Whereas p=11 then 2p/11 is 2. Since 2p/11 is both negative and positive, we can say B is insufficient. Can we use this?
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Joined: 02 Sep 2009
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22 Oct 2016, 00:35
vrgmat wrote:
Bunuel,

B is proved wrong by taking p=0. Can we also prove it wrong by taking p as negative? For instance if p is -11 then 2p/11 is -2. Whereas p=11 then 2p/11 is 2. Since 2p/11 is both negative and positive, we can say B is insufficient. Can we use this?

Yes, you can do this way too.
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22 Oct 2016, 20:35
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Bunuel wrote:
Is $$\frac{4p}{11}$$ a positive integer?

(1) $$p$$ is a prime number

(2) $$2p$$ is divisible by 11

Here from the statement 1 we know p is a positive number and it can be 2,3,5,7,11,13,17.........
So from this we cannot say 4p/11 is a positive integer or not
Consider Statement 2
given 2p/11 is divisible
so definitely 2 *(2p/11) is an integer but we cannot ensure that 4p/11 is positive or not
on combining equation 1 and 2 we can confirm that
Hence C
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Manager
Joined: 19 Jul 2016
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08 Jan 2017, 03:47
I think this is a high-quality question and I agree with explanation.
Intern
Joined: 21 May 2015
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26 Aug 2017, 03:55
I think this is a high-quality question and I agree with explanation.
Re M05-29   [#permalink] 26 Aug 2017, 03:55

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# M05-29

Moderators: chetan2u, Bunuel

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