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M05-29

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Intern
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Joined: 02 Sep 2016
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Re M05-29  [#permalink]

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New post 15 Oct 2016, 18:51
I think this is a high-quality question and I agree with explanation.
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Re: M05-29  [#permalink]

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New post 21 Oct 2016, 13:24
Bunuel,

B is proved wrong by taking p=0. Can we also prove it wrong by taking p as negative? For instance if p is -11 then 2p/11 is -2. Whereas p=11 then 2p/11 is 2. Since 2p/11 is both negative and positive, we can say B is insufficient. Can we use this?
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Re: M05-29  [#permalink]

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New post 22 Oct 2016, 01:35
vrgmat wrote:
Bunuel,

B is proved wrong by taking p=0. Can we also prove it wrong by taking p as negative? For instance if p is -11 then 2p/11 is -2. Whereas p=11 then 2p/11 is 2. Since 2p/11 is both negative and positive, we can say B is insufficient. Can we use this?


Yes, you can do this way too.
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Re: M05-29  [#permalink]

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New post 22 Oct 2016, 21:35
1
Bunuel wrote:
Is \(\frac{4p}{11}\) a positive integer?


(1) \(p\) is a prime number

(2) \(2p\) is divisible by 11


Here from the statement 1 we know p is a positive number and it can be 2,3,5,7,11,13,17.........
So from this we cannot say 4p/11 is a positive integer or not
Consider Statement 2
given 2p/11 is divisible
so definitely 2 *(2p/11) is an integer but we cannot ensure that 4p/11 is positive or not
on combining equation 1 and 2 we can confirm that
Hence C
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Re M05-29  [#permalink]

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New post 08 Jan 2017, 04:47
I think this is a high-quality question and I agree with explanation.
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Re M05-29  [#permalink]

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New post 26 Aug 2017, 04:55
I think this is a high-quality question and I agree with explanation.
Re M05-29 &nbs [#permalink] 26 Aug 2017, 04:55

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