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dolorumsimilique
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M06-07 16 Dec 2025, 07:32
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I like the solution - it’s helpful.
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commodiad
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M06-07 21 Dec 2025, 09:59
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I did not quite understand the solution. Please show how to get 2^8 from 256
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Bunuel
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M06-07 21 Dec 2025, 10:05
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commodiad
I did not quite understand the solution. Please show how to get 2^8 from 256
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Not sure how to show this but 2^8 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 = 256.
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M06-07 22 Dec 2025, 11:11
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I like the solution - it’s helpful.
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M06-07 10 Jan 2026, 16:08
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M06-07 17 Jan 2026, 02:26
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I like the solution - it’s helpful.
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M06-07 31 Jan 2026, 02:48
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can u elaborate more why we need to make n = 0, is it because of the m already covered ?
Bunuel


Here is an explanation:

Since both \(2^{90}\) and \(m\) are integers, then \(\frac{n}{2^8}\) must also be an integer. Considering the constraint \(0 \le n \le 4\), this is only possible when \(n = 0\).

So, n can only be 0, 1, 2, 3, or 4. Only if n is 0 do we get an integer value for n/2^8.
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M06-07 31 Jan 2026, 05:13
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sunshineeee
can u elaborate more why we need to make n = 0, is it because of the m already covered ?

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We have: \(2^{90} = m + \frac{n}{2^8}\).

Since 2^90 and m are integers, n/2^8 must also be an integer. But n is restricted to 0, 1, 2, 3, 4. None of those divided by 2^8 gives an integer, except 0. So the only possible value for n is 0.
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blanditiisoptio
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M06-07 09 Feb 2026, 02:43
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M06-07 Updated on: 17 Feb 2026, 01:25
Originally posted by Omomomo on 13 Feb 2026, 03:18.
Last edited by Omomomo on 17 Feb 2026, 01:25, edited 1 time in total.
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the question is worded in a confusing manner. they should've used brackets to specify whether its (256*m)+n or if its 256*(m+n), or they should've simply worded it as 256m+n.
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M06-07 13 Feb 2026, 03:52
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Omomomo
I don’t quite agree with the solution. the question should be worded in a confusing manner. they should've used brackets to specify whether its (256*m)+n or if its 256*(m+n), or they should've simply worded it as 256m+n.
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You are wrong. Mathematically, 256m + n can only mean (256m) + n, nothing more. If it were 256(m + n), it would have been written that way. So there is no ambiguity there whatsoever.
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M06-07 16 Mar 2026, 13:02
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I like the solution - it’s helpful.
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M06-07 24 Mar 2026, 06:33
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Here's how I did it, but this method is better applied to just this question instead of all questions of this type-

If n can be 0, try to check whether the equation can be solved just in terms of m. If you remove n, you get 2^98 = 256∗m

Since 256 = 2^8, you can rewrite this as 2^98=2^8 * m. Hence m will have to be 2^90.

n = 0 is sufficient.
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M06-07 25 Mar 2026, 20:30
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I like the solution - it’s helpful. Since m can only take a value 2^90, anything less than this will not result in 2^98, as n can take a max value of 4, so m= 2^90 and n= 0 is the only possibility.
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