Official Solution:

A circle with a radius \(r\) is inscribed in a square with side \(s\). If the ratio of the area of the square to the area of the circle is \(m\), and the ratio of the perimeter of the square to that of the circle is \(n\), which of the following must be true? (The area of a circle is \(\pi r^2\) and the perimeter of a circle is \(2 \pi r\)) A. \(\frac{m}{n} > 1\)
B. \(\frac{m}{n} = 1\)
C. \(1\gt \frac{m}{n} > \frac{1}{2}\)
D. \(\frac{m}{n} = \frac{1}{2}\)
E. \(\frac{m}{n} < \frac{1}{2}\)
Note that this is not a Geometry question. While it uses basic knowledge of figures, it is actually a Ratios question. There are 8 questions within GMAT Prep Focus Edition that use similar principles.
Here is one example.
Using a number-picking approach:
Assume \(s = 6\). For the inscribed circle, \(r = \frac{s}{2} = \frac{6}{2} = 3\). Consequently, the area of the square is \(6 * 6 = 36\) and the area of the circle is \(\pi*r^2 = 9\pi\). The ratio \(m\) is \(\frac{4}{\pi}\).
The perimeter of the square is \(4s=24\) and the perimeter of the circle is \(2\pi r = 6\pi\). The ratio \(n\) is \(\frac{4}{\pi}\).
Therefore, \(m = n\), so \(\frac{m}{n} = 1\).
Algebraic approach:
Using an algebraic approach:
"A circle with a radius \(r\) is inscribed in a square with side \(s\)" implies \(s = 2r\);
"The ratio of the area of the square to the area of the circle is \(m\)" can be written as \(m = \frac{s^2}{\pi{r^2} } = \frac{(2r)^2}{\pi{r^2} }=\frac{4}{\pi}\).
"The ratio of the perimeter of the square to that of the circle is \(n\)" can be stated as \(n = \frac{4s}{2\pi{r} }= \frac{4(2r)} { 2\pi{r} }=\frac{4}{\pi}\).
Therefore, \(m = n\), so \(\frac{m}{n} = 1\).
Answer: B