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Bunuel
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Bunuel
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Thanks Brunnel! That was a great breakdown of using the difference of two squares to solve this problem!
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I think this is a high-quality question. Another approach - 987 x 987 = (1000-13) x (1000-13) = (1000-13)^2
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The best way to solve this question (What is 987 * 987?) is by elimination method.

we know 987*987 has to be divisible by 9, since 987 is divisible by 3.
Using the divisor rule of 9 in the options: correct answer should be the one whose sum of digits is divisible by 9.

974,169= 36
974,219= 32
974,549= 38
975,019= 31
975,369= 39

only 36 is divisible by 9, so A is correct
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Use \((a-b)^2\) = \(a^2+b^2-2ab\) to solve the question.

987 * 987 = (1000-13)*(1000-13) = 1000^2+13^2-2*1000*13 = 1000000 + 169 - 26000 (STOP here) ...Don't solve it further. Just realise that the final solution will have 169 as the last 3 digits. Only option A has it. Correct Ans is A.
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I think the easier approach is that

987*987 = (1000-13)* (1000-13) = (1000-13)^2 = (1000)^2 + 13^2 -26000

Then because of 13^2 = 169, i should pick the choice with 169 at the tail. (1000^2 - 26000 will be a number with trailing zeros).
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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