AnikaJu wrote:
Bunuel wrote:
AnikaJu wrote:
Hi Icecream,
I did exactly the same!
In my opinion it is also a valid / possible way of solution.
@Bunuel, can you please advise?
Thanks!!
On what ground do you assume that the triangle is 30-60-90 triangle?
I know that the angle at point O is 90 degrees and the opposite of the angle of 90 degreed is 2x. x = 5.
However I must admit that I just assumed that the other two angles are 30 and 60, I cannot provide you a proof... mhmmmm
Thanks for your fast reply!
So I did the same way, and while it's not the best way to solve, there's actually a way to prove that the triangle is a 30-60-90 triangle:
Since the object is a rectangle, angle OCA = angle COB. Because the rectangle is inscribed in the circle, we can also say that sin(angle COB) = 5/10 = .5. sin(30) = .5 so we know angle COB = OCA = 30 degrees.
Like I said, this was not at all the best way to answer this question, and I was getting way too analytical about it, but there you go.