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# m09#8

Author Message
Manager
Joined: 14 Dec 2009
Posts: 77
Followers: 1

Kudos [?]: 37 [0], given: 20

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08 Feb 2010, 01:27
If both X and Y are positive integers and X/Y=2.625 , which of the following can be a remainder of X divided by Y?

(C) 2008 GMAT Club - m09#8

2
4
5
8
9

It follows from the stem that X=2Y+0.625Y. Therefore, the remainder can be expressed as 0.626Y=5/8*Y where Y is a positive integer. Then Y is a multiple of 8, and the remainder is a multiple of 5.

Can anybody give a detailed explanation? I don't understand the OE, particularly the last sentence.
Thank you

Last edited by Igor010 on 08 Feb 2010, 22:44, edited 1 time in total.
Senior Manager
Joined: 28 Jun 2009
Posts: 445
Location: United States (MA)
Followers: 18

Kudos [?]: 176 [0], given: 46

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08 Feb 2010, 16:23
Per my method answer is C.

Given: X/Y = 2.625

Plugging in method : X=21 and Y=8. This gives answers choice C i.e. 5
Manager
Joined: 14 Dec 2009
Posts: 77
Followers: 1

Kudos [?]: 37 [0], given: 20

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08 Feb 2010, 22:37
piyatiwari wrote:
Per my method answer is C.

Given: X/Y = 2.625

Plugging in method : X=21 and Y=8. This gives answers choice C i.e. 5

Could you elaborate your solution? This one is still unclear to me
Senior Manager
Joined: 28 Jun 2009
Posts: 445
Location: United States (MA)
Followers: 18

Kudos [?]: 176 [1] , given: 46

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09 Feb 2010, 07:24
1
KUDOS
I dont know how right this method is, but I always use this and 99% of the times the answer is right.

x/y = 2.625 = 2625/1000 = 105/40 = 21/8 => division 2 and reminder 5
Manager
Joined: 14 Dec 2009
Posts: 77
Followers: 1

Kudos [?]: 37 [0], given: 20

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09 Feb 2010, 22:28
piyatiwari wrote:
I dont know how right this method is, but I always use this and 99% of the times the answer is right.

x/y = 2.625 = 2625/1000 = 105/40 = 21/8 => division 2 and reminder 5

Thank you piyatiwari!
Folks! Can anybody confirm this method?
Re: m09#8   [#permalink] 09 Feb 2010, 22:28
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# m09#8

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