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Re M12-13 [#permalink]
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 16 Sep 2014, 00:46
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Re M12-13 [#permalink]
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30 Oct 2015, 07:45
I think this is a poor-quality question and the explanation isn't clear enough, please elaborate.
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Re: M12-13 [#permalink]
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30 Oct 2015, 08:12
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Re: M12-13 [#permalink]
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24 Nov 2015, 01:53
hi Bunuel can't A suffice to find solution? y=2x is given as going from quad 3 through origin to quad 1 with slope 2. slope of the perped line is -1/2, relatioship between points is given as whenever a is positive the b bears the same value but with opposite sign (10,-10 or -10;10) - hence the second line has to go through the origin from quad 2 to quad 4? thanks
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Re: M12-13 [#permalink]
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24 Nov 2015, 10:24
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Re: M12-13 [#permalink]
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02 Jul 2016, 03:38
Hi friends,
the line y=2x surely passes through the origin as the coordinates (0,0) satisfies the equation.
Now coming to the point, the solution says both the statements are required, but if you take the slope of second line as -1/2 then the equation for is
-1/2=(y-b)/(x-a)
or, 2y= -x +(a+b)
or, y=(-1/2)x+(a+b)/2
Now, applying statement 1 (a=-b)to this equation;
y=(-1/2)x+{a+(-a)}/2
or, y=(-1/2)x+ 0/2
or, y=(-1/2)x
So, statement 1 seems sufficient (contradiction with the actual answer)
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Re: M12-13 [#permalink]
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02 Jul 2016, 05:17
subhajit1 wrote: Hi friends,
the line y=2x surely passes through the origin as the coordinates (0,0) satisfies the equation.
Now coming to the point, the solution says both the statements are required, but if you take the slope of second line as -1/2 then the equation for is
-1/2=(y-b)/(x-a)
or, 2y= -x +(a+b)
or, y=(-1/2)x+(a+b)/2
Now, applying statement 1 (a=-b)to this equation;
y=(-1/2)x+{a+(-a)}/2
or, y=(-1/2)x+ 0/2
or, y=(-1/2)x
So, statement 1 seems sufficient (contradiction with the actual answer) Check the diagram below:  As you can see if a = 1 and b = -1 we have different line perpendicular to y = 2x than if a = 2 and b = -2.
>> !!!
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Re M12-13 [#permalink]
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24 Jul 2016, 00:34
I think this is a high-quality question and the explanation isn't clear enough, please elaborate. Bunuel,
If the intention is merely to find values of a and b then what is the significance of "Perpendicularity" here? Please explain
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Re: M12-13 [#permalink]
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24 Jul 2016, 02:42
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Re: M12-13 [#permalink]
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16 Aug 2016, 13:36
I think that this is a high-quality question and the explanation is very clear. Thanks for posting.
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Re: M12-13 [#permalink]
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17 Aug 2016, 06:30
S1) take different values for a,b that meet the given statement (a=-b) and form lines equations of lines with slope -1/2. You can see that for different values of (a,b), you get different equations.
S2) same as statement 1
Both) Both equations give a point a=1/2 and b=-1/2. Which hivea only one equation 2x+4y=-1
So the ans is C. Hope fully my logic ia correct.
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Re: M12-13 [#permalink]
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07 Oct 2016, 13:30
Bunuel wrote: subhajit1 wrote: Hi friends,
the line y=2x surely passes through the origin as the coordinates (0,0) satisfies the equation.
Now coming to the point, the solution says both the statements are required, but if you take the slope of second line as -1/2 then the equation for is
-1/2=(y-b)/(x-a)
or, 2y= -x +(a+b)
or, y=(-1/2)x+(a+b)/2
Now, applying statement 1 (a=-b)to this equation;
y=(-1/2)x+{a+(-a)}/2
or, y=(-1/2)x+ 0/2
or, y=(-1/2)x
So, statement 1 seems sufficient (contradiction with the actual answer) Check the diagram below: As you can see if a = 1 and b = -1 we have different line perpendicular to y = 2x than if a = 2 and b = -2. i want to apologize, as i am very very weak at coordinate geometry. First, please give a suggestion how can i learn coordinate geometry. 2nd, isn't it obvious in option A that b=5, a= -5; b= 1 a= -1; b=0, a=0; b=1, a= -1? sorry again if i ask something foolish
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Re: M12-13 [#permalink]
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08 Oct 2016, 03:16
nahid78 wrote: Bunuel wrote: subhajit1 wrote: Hi friends,
the line y=2x surely passes through the origin as the coordinates (0,0) satisfies the equation.
Now coming to the point, the solution says both the statements are required, but if you take the slope of second line as -1/2 then the equation for is
-1/2=(y-b)/(x-a)
or, 2y= -x +(a+b)
or, y=(-1/2)x+(a+b)/2
Now, applying statement 1 (a=-b)to this equation;
y=(-1/2)x+{a+(-a)}/2
or, y=(-1/2)x+ 0/2
or, y=(-1/2)x
So, statement 1 seems sufficient (contradiction with the actual answer) Check the diagram below: As you can see if a = 1 and b = -1 we have different line perpendicular to y = 2x than if a = 2 and b = -2. i want to apologize, as i am very very weak at coordinate geometry. First, please give a suggestion how can i learn coordinate geometry. 2nd, isn't it obvious in option A that b=5, a= -5; b= 1 a= -1; b=0, a=0; b=1, a= -1? sorry again if i ask something foolish For coordinate geometry check this: math-coordinate-geometry-87652.htmlFor more on this question check here: what-is-the-equation-of-the-line-k-that-is-perpendicular-to-line-y-69481.html
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat
DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics
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Re: M12-13 [#permalink]
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20 Dec 2016, 06:23
Hi Bunuel,
A little clarification
equation of line perpendicular to y-2x=0 will be -2y-x+c=0 ??
In order to find equation of a line perpendicular to ax+by+c=0.....interchange coefficients of x and y and change the sign in between....so equation of line perpendicular to ax+by+c=0 will be bx-ay+k=0.
Is this approach correct?
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Re M12-13 [#permalink]
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27 Dec 2016, 11:18
I think this is a high-quality question and I agree with explanation.
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Hi Bunuel,
If the question were to be a slightly different one, would the below Statement be sufficient?
Question stem: Find equation of the line K, perpendicular to a line y= -1/2x and passes through point (a,b).
statement 1) 2a=b
I understood the point that given a slope + either the y-intercept or a specific point, we can plot the specific line. Where I am getting confused is whether we can still identify the line by having the slope and a generic equation such as 2a=b.
When I tried plotting several lines with the slope = 2 and with different y-intercepts, I could not come up with any point that satisfy 2a=b and any other lines except y=2x+0.
Would you please help me clear this point? Thanks!
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Re: M12-13 [#permalink]
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17 Apr 2017, 02:15
I do not understand why we cannot say that stat I implies a=b=0, hence being sufficient while statement II implies basically all consecutive integers, not being sufficient. Can someone please explain?
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Re: M12-13 [#permalink]
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17 Apr 2017, 02:20
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Re: M12-13 [#permalink]
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10 Sep 2017, 22:59
Hi, Can anyone tell me what will be the final equation of the line once we know what a and b are?
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