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# M12-23

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Math Expert
Joined: 02 Sep 2009
Posts: 51035

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15 Sep 2014, 23:47
1
00:00

Difficulty:

35% (medium)

Question Stats:

66% (00:31) correct 34% (00:42) wrong based on 131 sessions

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How many subsets of $$\{a,b,c,d\}$$ including both $$a$$ and $$c$$ (order of elements does not matter) are there?

A. 3
B. 4
C. 5
D. 6
E. 7

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 51035

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15 Sep 2014, 23:47
Official Solution:

How many subsets of $$\{a,b,c,d\}$$ including both $$a$$ and $$c$$ (order of elements does not matter) are there?

A. 3
B. 4
C. 5
D. 6
E. 7

Here are the four subsets: $$\{a, c\}, \ \{a, b, c\}, \ \{a, c, d\}, \ \{a, b, c, d\}$$.

_________________
Intern
Joined: 11 May 2014
Posts: 2
Schools: Haas '17, IE Sept'16

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15 Jan 2015, 10:22
I think this question is good and helpful.
Is there a way to solve with combinatorics?
Current Student
Joined: 14 May 2014
Posts: 42
Schools: Broad '18 (WA)
GMAT 1: 700 Q44 V41
GPA: 3.11

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24 Jul 2015, 08:27
Bunuel wrote:
Official Solution:

How many subsets of $$\{a,b,c,d\}$$ including both $$a$$ and $$c$$ (order of elements does not matter) are there?

A. 3
B. 4
C. 5
D. 6
E. 7

Here are the four subsets: $$\{a, c\}, \ \{a, b, c\}, \ \{a, c, d\}, \ \{a, b, c, d\}$$.

hi, Bunuel,

can we count {a,b,c,d} as subset of {a,b,c,d}..?
Math Expert
Joined: 02 Sep 2009
Posts: 51035

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24 Jul 2015, 08:31
riyazgilani wrote:
Bunuel wrote:
Official Solution:

How many subsets of $$\{a,b,c,d\}$$ including both $$a$$ and $$c$$ (order of elements does not matter) are there?

A. 3
B. 4
C. 5
D. 6
E. 7

Here are the four subsets: $$\{a, c\}, \ \{a, b, c\}, \ \{a, c, d\}, \ \{a, b, c, d\}$$.

hi, Bunuel,

can we count {a,b,c,d} as subset of {a,b,c,d}..?

____________________________
Yes.
_________________
Intern
Joined: 14 Oct 2015
Posts: 31
GMAT 1: 640 Q45 V33

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29 Oct 2015, 07:54
Bunuel wrote:
riyazgilani wrote:
Bunuel wrote:
Official Solution:

How many subsets of $$\{a,b,c,d\}$$ including both $$a$$ and $$c$$ (order of elements does not matter) are there?

A. 3
B. 4
C. 5
D. 6
E. 7

Here are the four subsets: $$\{a, c\}, \ \{a, b, c\}, \ \{a, c, d\}, \ \{a, b, c, d\}$$.

hi, Bunuel,

can we count {a,b,c,d} as subset of {a,b,c,d}..?

____________________________
Yes.

That does not make sense. How can a "sub" set be the same as the set?? {a,b,c,d} is not a subset of {a,b,c,d}. Agree to disagree.
Math Expert
Joined: 02 Sep 2009
Posts: 51035

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29 Oct 2015, 10:42
1
danjbon wrote:
Bunuel wrote:
riyazgilani wrote:

hi, Bunuel,

can we count {a,b,c,d} as subset of {a,b,c,d}..?

____________________________
Yes.

That does not make sense. How can a "sub" set be the same as the set?? {a,b,c,d} is not a subset of {a,b,c,d}. Agree to disagree.

Mathematically B is a subset of A if every member of B is a member of A. So, a set is a subset of itself.
_________________
Intern
Joined: 15 Dec 2014
Posts: 8
Concentration: Strategy, General Management
Schools: Rotman '18
GMAT 1: 610 Q44 V31

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19 Jan 2016, 08:21
Buenel,

I have a (naive) question. Why (D,A,C,B) is not a subset of (A,B,C,D) - when order of elements doesn't matter ?
Math Expert
Joined: 02 Sep 2009
Posts: 51035

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19 Jan 2016, 08:25
1
cricketer wrote:
Buenel,

I have a (naive) question. Why (D,A,C,B) is not a subset of (A,B,C,D) - when order of elements doesn't matter ?

A set, by definition, is a collection of elements without any order. (While, a sequence, by definition, is an ordered list of terms.)
_________________
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Joined: 15 Dec 2014
Posts: 8
Concentration: Strategy, General Management
Schools: Rotman '18
GMAT 1: 610 Q44 V31

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19 Jan 2016, 08:31
Bunuel wrote:
cricketer wrote:
Buenel,

I have a (naive) question. Why (D,A,C,B) is not a subset of (A,B,C,D) - when order of elements doesn't matter ?

A set, by definition, is a collection of elements without any order. (While, a sequence, by definition, is an ordered list of terms.)

Thanks a lot. Very helpful/useful concept.
Current Student
Joined: 19 Jun 2016
Posts: 1
Location: India
Schools: ISB '18 (A)
GMAT 1: 710 Q50 V34
GPA: 3.5

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10 Oct 2016, 21:28
I think this is a poor-quality question. Useless question
Manager
Joined: 27 Oct 2014
Posts: 156
Location: India
GMAT 1: 760 Q50 V41
GPA: 4
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15 Jul 2017, 11:40
Can this question be re-worded to say "include both a & c"?
_________________

If you found this post useful, hit Kudos! :D

Joined: 08 Feb 2017
Posts: 80
Concentration: Entrepreneurship, Marketing
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23 Jul 2017, 08:36
Why we don't consider singletons? (Set of one number here).
Math Expert
Joined: 02 Sep 2009
Posts: 51035

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23 Jul 2017, 19:49
Evgart wrote:
Why we don't consider singletons? (Set of one number here).

Doesn't the question say that the subsets must include at least both a and c?
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Joined: 26 Dec 2015
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14 Aug 2017, 07:19
why not {a,d} and {b,d}?
Math Expert
Joined: 02 Sep 2009
Posts: 51035

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14 Aug 2017, 07:24
frndabu1 wrote:
why not {a,d} and {b,d}?

Because the subsets must include both a and c. Neither {a, d} nor {b, d} include both a and c.
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Joined: 26 Dec 2015
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14 Aug 2017, 07:45
Manager
Joined: 23 Jun 2016
Posts: 99

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07 Nov 2017, 11:11
the number of subsets from k elements is 2^k
here if we consider a and c together as one element (since they are always present together), won't the number of subsets: 2^3 = 8?
now a&c will always need to be present, therefore the only remaining subsets: 2^2 = 4

is above understanding correct?
Manager
Joined: 21 Jul 2017
Posts: 193
Location: India
Concentration: Social Entrepreneurship, Leadership
GMAT 1: 650 Q47 V33
GPA: 4
WE: Project Management (Education)

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26 Oct 2018, 12:18
Bunuel wrote:
Official Solution:

How many subsets of $$\{a,b,c,d\}$$ including both $$a$$ and $$c$$ (order of elements does not matter) are there?

A. 3
B. 4
C. 5
D. 6
E. 7

Here are the four subsets: $$\{a, c\}, \ \{a, b, c\}, \ \{a, c, d\}, \ \{a, b, c, d\}$$.

Dear Bunuel,

Is there any other way to approach alike questions. What if the subsets were asked for {a, b, c, d, e, f, g}?
Manager
Joined: 14 Aug 2012
Posts: 93
GMAT 1: 620 Q43 V33

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04 Nov 2018, 09:34
Is this fair game on the real test? I haven't seen subsets covered anywhere. Any reference material would be helpful....
Re: M12-23 &nbs [#permalink] 04 Nov 2018, 09:34
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# M12-23

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