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Math Expert
Joined: 02 Sep 2009
Posts: 51123

Question Stats:
59% (00:54) correct 41% (01:02) wrong based on 101 sessions
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Math Expert
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Re M1404
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15 Sep 2014, 23:50



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Joined: 13 Dec 2015
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Re: M1404
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05 Sep 2016, 19:13
Hello, what is the shortest working out steps to find the common divisor?



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Joined: 07 Feb 2016
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GMAT 1: 650 Q47 V34 GMAT 2: 710 Q48 V39

Re: M1404
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07 May 2017, 00:39
unleesooj wrote: Hello, what is the shortest working out steps to find the common divisor? I did prime factorization in order to calculate the number of factors: \(48=2^4*3^1\) \(factors=5*2=10\) and then divided 48 by ascending numbers: \(48/1\) \(48/2\) \(48/3\) \(48/4\) \(...\) This took me 2:15 for this question. Nevertheless, the very first step is not necessary, it was helping me not to forget any factor.



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Re: M1404
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07 May 2017, 02:17
36=1,2,3,4,6,9,12,18,36 48=1,2,3,4,6,8,12,16,24,48 common sum=1+2+3+4+6+12=28 ans: E



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Re: M1404
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16 Jun 2017, 10:59
1. Find the GCD of the numbers 2. Factors of GCD are also factors of the two numbers > List out all the factors of the GCD. 3. Sum them up.



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Quote: 1. Find the GCD of the numbers 2. Factors of GCD are also factors of the two numbers > List out all the factors of the GCD. 3. Sum them up. BunuelCould you please confirm whether the above method should hold true for general cases? IMO the GCD should have all the common factors of a list of numbers. And there is that general formula to calculate the sum of all factors of a number, using which we can calculate the sum of factors of GCD. This should ideally provide a generic method to arrive at the sum of common factors for all numbers? Please correct me if I am mistaken. Thanks



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Re: M1404
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23 Aug 2018, 21:52



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Joined: 21 Jun 2017
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Concentration: Finance, Economics
WE: Corporate Finance (Commercial Banking)

Hi guys, Any shorter way to do this. This took me 3.5+ minutes. listed down all factors by brute force Please guide
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Joined: 28 Jun 2018
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GMAT 1: 490 Q39 V18 GMAT 2: 640 Q47 V30 GMAT 3: 670 Q50 V31 GMAT 4: 700 Q49 V36
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ShankSouljaBoi wrote: Hi guys, Any shorter way to do this. This took me 3.5+ minutes. listed down all factors by brute force Please guide Hi, 1.Write down prime factorization of both numbers. \(48 = 3 * 2^4\) \(36 = 3^2 * 2^2\) 2. Next find GCD of the numbers. GCD \(= 3 * 2^2\) (To find GCD just write down the common prime factors. Then choose their lowest powers.) 3.Write down all the numbers u can make from this factorization.\(1, 2, 3, 3*2 , 3*2*2 , 2*2\) Sum them up! And you have the answer. This can be done within 2 minutes easily if u just be careful and practice step 3! Hope it helps!










