mrinal2100
there is a question in test m15
a^2-b^2=b^2-c^2.Is a=|b|
1)b=|c|
2)b=|a|
from 1 we get a^2=b^2
a=root b^2
or a=|b|
but in answer its given
a^2=b^2
so |a|=|b|
i have doubt regarding mod
|a|=root a^2
so above
how can we write a^2=|a|I guess your main question is about the following issue is why is \(\sqrt{x^2}=|x|\) true.
The point here is that as
square root function can not give negative result then \(\sqrt{some \ expression}\geq{0}\).
So \(\sqrt{x^2}\geq{0}\). But what does \(\sqrt{x^2}\) equal to?
Let's consider following examples:
If \(x=5\) --> \(\sqrt{x^2}=\sqrt{25}=5=x=positive\);
If \(x=-5\) --> \(\sqrt{x^2}=\sqrt{25}=5=-x=positive\).
So we got that:
\(\sqrt{x^2}=x\), if \(x\geq{0}\);
\(\sqrt{x^2}=-x\), if \(x<0\).
What function does exactly the same thing? The absolute value function: \(|x|=x\), if \(x\geq{0}\) and \(|x|=-x\), if \(x<0\). That is why \(\sqrt{x^2}=|x|\).
Hope it helps.