Bunuel
Is \(|x - y| \gt |x + y|\)?
(1) \(x^2 - y^2 = 9\)
(2) \(x - y = 2\)
With many of the questions related to simplifying the initial question as - Is xy<0?-, let me give two ways to solve it, thereby clearing the doubt around xy<0.
Method ILet us not simplify the initial question. But why?
Because the initial question and the statements are in expressions x-y and x+y or \(x^2-y^2\), which is a product of those two terms.
(1) \(x^2 - y^2 = 9........(x-y)(x+y)=9=1*9\)
So x-y and x+y can have values 1 and 9 respectively or 9 and 1 respectively.
The answer will be different in both the cases.
(2) \(x - y = 2\)
Nothing about x+y
Combined
x-y=2, so (x-y)(x+y)=2(x+y)=9.
So x+y=4.5
As x-y and x+y are positive, the question is: Is 2>4.5?
The answer is NO.
Sufficient
Method II\(|x-y|>|x+y|\) will be true only when x and y have opposite sign or xy<0.
As seen above we cannot solve the inequality by any of the statements individually.
Combined
x-y=2 and x+y=4.5
Add both the equations
2x=6.5 or x=3.25 and y = 3.25-2=1.25
So, the answer for xy<0 is no as xy=3.25*1.25
Sufficient
C