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M15-26

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Bunuel
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M15-26 [#permalink] New post   16 Sep 2014, 00:56
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74% (02:27) correct 26% (02:52) wrong based on 128 sessions
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Two different acid solutions were combined to create a 10-liter mixture. The first solution contained 0.8 liters of acid, while the second solution contained 0.6 liters of acid. If the concentration of acid in the first solution was twice that of the second solution, what was the volume of the first solution?

A. 3.0 liters
B. 3.2 liters
C. 3.6 liters
D. 4.0 liters
E. 4.2 liters
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Bunuel
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Re M15-26 [#permalink] New post   16 Sep 2014, 00:56
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Official Solution:

Two different acid solutions were combined to create a 10-liter mixture. The first solution contained 0.8 liters of acid, while the second solution contained 0.6 liters of acid. If the concentration of acid in the first solution was twice that of the second solution, what was the volume of the first solution?

A. 3.0 liters
B. 3.2 liters
C. 3.6 liters
D. 4.0 liters
E. 4.2 liters


Let \(x\) be the volume of the first solution. Since the total volume is 10 liters, the volume of the second solution is \(10-x\). Using the given information, we form the equation \(\frac{0.8}{x} = 2*\frac{0.6}{10 - x}\), representing the acid concentration in the first solution being twice that in the second solution. Solving for \(x\), we find the volume of the first solution to be \(x = 4\) liters.


Answer: D
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Manoraaju
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Re: M15-26 [#permalink] New post   25 Jun 2017, 00:48
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I used an another method which works.

Solution A1 (0.8 litres)
Solution A2 (0.6 litres)

A1+A2=10

(0.8/A1)=2*(0.6/A2)

Therefore A2=1.5A1

A1+1.5A1 =10

A1= 10/2.5 = 4 litres.
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saplogics
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Re: M15-26 [#permalink] New post   06 Sep 2018, 09:13
I think this is a high-quality question and I agree with explanation. I used a different approach: Solicit your opinion on it.

First solution has 0.8 lt Acid.
We also know the concentration of acid is twice that of the second solution.
So, if sample 1 had same concentration then sample1 would contain 0.4 lt acid.
Now we got a ratio between volumes between the two different solutions.
0.4:0.6 which is 2:3
We can say there was 4 liter of solution 1 in 10 liter of mixed solution.

Let me know your opinion on it.
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Re: M15-26 [#permalink] New post   27 May 2021, 08:04
Need to practice these kind of questions. Is there any thread for these mixture questions of various level(500-700+)?
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Bunuel
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Re: M15-26 [#permalink] New post   27 May 2021, 09:50
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kri1311 wrote:
Need to practice these kind of questions. Is there any thread for these mixture questions of various level(500-700+)?


Check our questions bank: https://gmatclub.com/forum/search.php?view=search_tags

18. Mixture Problems



For more check Ultimate GMAT Quantitative Megathread



Hope it helps.
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Bunuel
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Re: M15-26 [#permalink] New post   18 Apr 2023, 09:14
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M15-26 [#permalink]
18 Apr 2023, 09:14
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