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ykaiim
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ykaiim
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ykaiim
lagomez,

I think AB, BC and AC represents sides.

You are right, still same answer.

2AB = 12
AB = 6

3BC = 12
BC =4

4AC = 12
AC = 3

you have a 3-4-6 triangle so one angle is over 90 because if one angle was 90 the ratio would have been 3-4-5 and less than 90 3-4-and a number less than 5

Part 2.

3-3-3 triangle
vs 3-4-6
6^2 + 3^2 > 4^2 sufficient and one angle greater than 90

9 + 9 > 9 sufficient but all angles less than 90
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1)
2AB = 3BC = 4AC -> AB = 6X, BC = 4X, AC = 3X

AB^2 > BC^2 + AC^2, so there is one angle bigger than 90°. The answer fo the question is "YES" and therefore statement 1) is Suff.

[strike]2) The square of one side is smaller then the sum of the squares of the other sides, so there is no angle bigger than 90°. The answer to the question is "NO" and therefore statement 2) is Suff[/strike].

My mistake. :oops: In the statement 2) you could have a rectangle, equilateral or obtusangle triangles, thefreore it is Insuff.
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Well, S2 in insufficient.

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