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Bunuel
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Rates: 40/x
40/(x+4)

40/x*6+40/(x+4)*6=50
240/x+240/(x+4)=50
240(x+4)+240x=50x(x+4)
240x+960+240x=50x^2+200x
0=50x^2-280x-960
0=5x^2-28x-96
0=(5x+12)(x-8)
x=8

40/12 t = 80
t=24 min
Answer D
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Bunuel
It takes printer A 4 more minutes than printer B to print 40 pages. If working together, the two printers can print 50 pages in 6 minutes, how long will it take printer A to print 80 pages?

A. 12
B. 18
C. 20
D. 24
E. 30

Tried to find correct answer through POE and solved in less than 2 mins and you can also reach to correct ans if you don't have superb knowledge which required to use above described method, Following are the steps which I followed.

1) Try to plugin value of option C(medium value) 80/20 = 4 PPM (Pages Per Min), hence in 6 min A will print 24 pages hence B will print 26 pages hence B will print 26/6 PPM but calculation will get difficult if you try to prove 1st condition and GMAT never give difficult calculations as it tests your logic skills and not calculation skills.

2) Try with option B 80/18 = 40/9 PPM, hence in 6 Min A will print 40/9 * 6 = 26 pages which is not possible as A can not print more than 50% of pages in total contribution of 50 pages as it works slow than B.

3) Now You can also eliminate option A as Printer A can not take less than 18 Min. Hence Option A, B, and C is canceled and left with D and E.

4) Try with option D 80/24 = 10/3 PPM, hence in 6 min Printer A will print 10/3 * 6 = 20 pages and B will print 50-20 = 30 Pages. Hence B can print 30/6 = 5 PPM
Now plug in this value for 1st condition and you will find that A will print 40 pages in 12 min and B will print 40 pages in 8 min. Got your ans.

This looks like time consuming but it is not if you perform most of the steps in Brain and not Paper.


Hi chetan2u, Bunuel,

Could you please advise if I have followed any incorrect steps to reach right answer.
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Hi Bunuel do you have links to similar questions please?
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I think this is a high-quality question and I agree with explanation. Was able to solve little bit but later got stuck loved the divide by 40 step really makes all the calulations easy
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I have an easy way.

40 page difference is 4 min,
50 page difference will be 5 min

let B takes x min so A will take x+5 min.

now x(x+5) whole divided by x+(x+5) should be equal to 6 solve for x

x=10

So B takes 10 min for 50 page and A takes 15 min for 50 page, now use linear eqn to get A time for 80 page which will be 24 mins
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Hi Bunuel,
Why did you decide to solve the question with respect to printer A, i.e. taking the time to print 40 pages to be 'a', and for B it becomes'a-4'? How did you know that solving this way will save time? At the end everything fell in place and you did not had to solve for 'a'. The way I solved it was a mess at the end, started with time for printer B to print 40 pages = t mins, time for printer A = t+4 mins.
Was stuck solving this:
5/24 = 1/(t+4) + 1/t
Can't plug in the answers for 't'.
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ADhanjal
Hi Bunuel,
Why did you decide to solve the question with respect to printer A, i.e. taking the time to print 40 pages to be 'a', and for B it becomes'a-4'? How did you know that solving this way will save time? At the end everything fell in place and you did not had to solve for 'a'. The way I solved it was a mess at the end, started with time for printer B to print 40 pages = t mins, time for printer A = t+4 mins.
Was stuck solving this:
5/24 = 1/(t+4) + 1/t
Can't plug in the answers for 't'.

The question specifically asks about printer A’s time, so it’s natural to assign the variable to A first. That way, whatever you solve or back‐solve directly answers the question without extra conversion. If you start with B, you just create an extra step for yourself.
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So, would you suggest solving questions like these with respect to the reference point in the question? I find it very difficult sometimes to solve for the variable especially in work/rate problems and distance/speed problems.
Bunuel
ADhanjal
Hi Bunuel,
Why did you decide to solve the question with respect to printer A, i.e. taking the time to print 40 pages to be 'a', and for B it becomes'a-4'? How did you know that solving this way will save time? At the end everything fell in place and you did not had to solve for 'a'. The way I solved it was a mess at the end, started with time for printer B to print 40 pages = t mins, time for printer A = t+4 mins.
Was stuck solving this:
5/24 = 1/(t+4) + 1/t
Can't plug in the answers for 't'.

The question specifically asks about printer A’s time, so it’s natural to assign the variable to A first. That way, whatever you solve or back‐solve directly answers the question without extra conversion. If you start with B, you just create an extra step for yourself.
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ADhanjal
So, would you suggest solving questions like these with respect to the reference point in the question? I find it very difficult sometimes to solve for the variable especially in work/rate problems and distance/speed problems.
Bunuel
ADhanjal
Hi Bunuel,
Why did you decide to solve the question with respect to printer A, i.e. taking the time to print 40 pages to be 'a', and for B it becomes'a-4'? How did you know that solving this way will save time? At the end everything fell in place and you did not had to solve for 'a'. The way I solved it was a mess at the end, started with time for printer B to print 40 pages = t mins, time for printer A = t+4 mins.
Was stuck solving this:
5/24 = 1/(t+4) + 1/t
Can't plug in the answers for 't'.

The question specifically asks about printer A’s time, so it’s natural to assign the variable to A first. That way, whatever you solve or back‐solve directly answers the question without extra conversion. If you start with B, you just create an extra step for yourself.

Ir depends on a question but generally yes.
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I like the solution - it’s helpful. What happens if you use a for B and a+4 for A?
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I like the solution - it’s helpful. What happens if you use a for B and a+4 for A?

First of all, you mentioned a and a+4, but it should be b and b+4. Next, the question specifically asks about printer A’s time, so it’s more natural to assign the variable to A first. That way, once you solve the equation or back-solve, you directly get A’s time without any extra conversion. If you start with B and write A as b+4, you’ll still reach the same solution, but you’ll need extra steps at the end to translate B’s value into A’s. So it would be possible to reach the answer, but it would be less convenient than the approach shown in the solution.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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ANother way to look at this is A has to print 80 pages that will be twice the time for 40 pages so options for 40 pages are

A. 12/2 = 6 So B is 2 => 1/ 6 + 1/2 =
B. 18/2 = 9 , B is 5 => 1/ 9 + 1/5
C. 20/2 = 10, B is 6 => 1/10+ 1/6 = 16/60
D. 24/2 = 12, B is 8 => 1/12 + 1/8 = 5/24
E. 30/2 = 15, B is 11 = > 1/ 15 + 1/11
Now we know that how much portion of 40 pages work in happening in 1 min

If both can print 50 pages in 6 mins
So they can together print 40 pages in 6*4/5 24/5 mins. So we need above values to be 5/24 work in 1 min . Answer is D
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This is a great question that’s helpful for learning.
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