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Bunuel
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Bunuel
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buddyisraelgmat
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Hello Bunuel

Could you please help me with this one - I didn't understand the explanation.
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Hello Bunuel

Could you please help me with this one - I didn't understand the explanation.

Not sure if this is still helpful to you ... it's been a few months since you posted the question, but here is some clarify:

1 line: 1+1 = 2 pieces -- straight forward
2 lines: carry the 2 pieces from the last one + 2 lines = 4 pieces
3 lines: carry the 4 from the last one + 3 lines = 7 pieces
4 lines: carry the 7 from the last one + 4 lines = 11 pieces


Hope this helps you!
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Nice question/solution Bunuel, got it by drawing the figure though :p
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I think this is a high-quality question and I agree with explanation.
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Although answered incorrectly, I liked this question after reading the solution. Can someone post such similar questions? Thanks!

I believe this is true for any shape, need not necessarily be a circle? Am I correct?
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wow this problem is really good for maximum pieces we have to divide the pie into unequal parts and make sure that lines do not pass through intersection points. Then we will maximum pieces.
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Attachment:
Circle With lines.jpg
Circle With lines.jpg [ 71.76 KiB | Viewed 17561 times ]

There is nothing much one can do when you draw the first line. The circle will be divided intwo two parts.

When you draw the second line then you have a choice, either you can interest the first line or not? Obviously when the second line intersects the first line within the circle then you have more divisions, i.e. 4 in all.

So one can learn from step two to draw the third line which will intersect as many lines as possible within the circle. I.e. third line intersecting the first two lines. Similarly the fourth line intersecting the first three lines, giving us 11 parts.
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:cry: this question ..... is just too much of a trap
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good question
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Nice question.

If it had been 14 in the answer choices, that would have been the highest number.

Three vertical cuts and one horizontal cut.

Given that we don´t have 14, 11 is the correct one.
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Josvit
Nice question.

If it had been 14 in the answer choices, that would have been the highest number.

Three vertical cuts and one horizontal cut.

Given that we don´t have 14, 11 is the correct one.
­Three vertical cuts and one horizontal cut give 8 pieces, not 14. 11 is the maximum number. 
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Nice question. Maximize the intersections when drawing the figure.
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