Official Solution:If 8 apples and 10 oranges cost as much as 22 apples and 4 oranges, how much does a combination of 7 oranges and 3 apples cost? Let \(o\) denote the price of an orange and \(a\) the price of an apple. We know from the stem that \(8a + 10o = 22a + 4o\), which gives \(14a = 6o\) and finally we get \(\frac{o}{a} = \frac{7}{3}\).
(1) An orange costs $0.04 more than an apple.
The above provides another equation: \(o = a + 0.04\). After solving the system of two linear equations for \(a\) and \(o\), we will be able to answer the question. Sufficient.
(2) The ratio of the price of an orange to the price of an apple is 7:3.
The above implies that \(\frac{o}{a} = \frac{7}{3}\). As we can see (2) just re-states the fact we already knew from the stem. So, it adds no additional useful info. Not sufficient.
Answer: A