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M22-29

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M22-29  [#permalink]

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New post 16 Sep 2014, 01:17
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  25% (medium)

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66% (00:42) correct 34% (00:41) wrong based on 145 sessions

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A car went from town A to town B. The distance between the towns is 200 miles. If at the half-way point the time was 9:00 am, when did the car arrive at town B ?


(1) The car began its journey at 7:00 am

(2) The average speed of the car over the second half was 40 mph

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Re M22-29  [#permalink]

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New post 16 Sep 2014, 01:17
Official Solution:


Statement (1) by itself is insufficient. We need to know more about the second half of the trip.

Statement (2) by itself is sufficient. The car covered the last 100 miles in \(\frac{100}{40}\) hours. Adding this time to 9:00 am we can find the arrival time.


Answer: B
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Collection of Questions:
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DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: M22-29  [#permalink]

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New post 31 Dec 2017, 04:35
Bunuel wrote:
Official Solution:


Statement (1) by itself is insufficient. We need to know more about the second half of the trip.

Statement (2) by itself is sufficient. The car covered the last 100 miles in \(\frac{100}{40}\) hours. Adding this time to 9:00 am we can find the arrival time.


Answer: B


Hi, Bunuel!
Please clear my doubt.

for statement 1) We have the distance=100 miles covered till half point of the journey and time taken to cover this distance= 9- 7 a.m = 2 hours. So, with this information we can calculate the speed of the journey = 100/2 = 50 miles/hour. With the help of speed and rest distance of 2nd half= 100 miles, I can calculate the time required to reach point B i.e t=100/50= 2 hours. This would tell me that the person reached at B at 9a.m + 2 hours = 11 a.m.
So statement 1 should have been sufficient.

Statement 2 is sufficient since we have the distance=100 miles and speed given. So time can be calculated to reach B.
That's why I chose Option D.

Please tell me where am I committing mistake?
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Re: M22-29  [#permalink]

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New post 01 Feb 2018, 09:27
1
Blossom1907 wrote:
Bunuel wrote:
Official Solution:


Statement (1) by itself is insufficient. We need to know more about the second half of the trip.

Statement (2) by itself is sufficient. The car covered the last 100 miles in \(\frac{100}{40}\) hours. Adding this time to 9:00 am we can find the arrival time.


Answer: B


Hi, Bunuel!
Please clear my doubt.

for statement 1) We have the distance=100 miles covered till half point of the journey and time taken to cover this distance= 9- 7 a.m = 2 hours. So, with this information we can calculate the speed of the journey = 100/2 = 50 miles/hour. With the help of speed and rest distance of 2nd half= 100 miles, I can calculate the time required to reach point B i.e t=100/50= 2 hours. This would tell me that the person reached at B at 9a.m + 2 hours = 11 a.m.
So statement 1 should have been sufficient.

Statement 2 is sufficient since we have the distance=100 miles and speed given. So time can be calculated to reach B.
That's why I chose Option D.

Please tell me where am I committing mistake?

-----------------

Hi, from statement 1 it is not evident whether the car is travelling at a constant speed throughout the journey. There is a possibility that the average speed during the second trip would be different from the first half. This information is not given. Hope it clarifies.
Re: M22-29 &nbs [#permalink] 01 Feb 2018, 09:27
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