Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
19 Feb 2013, 23:52
Kudos
Bookmarks
Hi
Sorry , I don't know how to format it correctly here, so pasting the image.
My doubt is .. If we take 5 raised to 4 as common in the denominator,
we will be left with
[5 raised to 4 ( 5 raised to 3 - 1 ) ] raised to -2.
Now this can be deduced to
5 raised to 2 * [5 raised to 3 - 1 ] raised to -2 ..
So 25 remains in the denominator .
However , if we do not take 5 raised to 4 as common in the denominator, the entire denominator can be taken above in the numerator by changing the sign of the exponent to positive 2.
In this case no 25 remains in the denominator.
I don't understand where I am going wrong . Kindly help.
Sorry , I don't know how to format it correctly here, so pasting the image.
My doubt is .. If we take 5 raised to 4 as common in the denominator,
we will be left with
[5 raised to 4 ( 5 raised to 3 - 1 ) ] raised to -2.
Now this can be deduced to
5 raised to 2 * [5 raised to 3 - 1 ] raised to -2 ..
So 25 remains in the denominator .
However , if we do not take 5 raised to 4 as common in the denominator, the entire denominator can be taken above in the numerator by changing the sign of the exponent to positive 2.
In this case no 25 remains in the denominator.
I don't understand where I am going wrong . Kindly help.
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block below for better discussion and related questions.
Thank you for understanding, and happy exploring!
21 Feb 2013, 11:06
Kudos
Bookmarks
There is no denominator to worry about, move the denominator to the numerator and change the sign to positive.
(3^5 - 3^2)^2 * (5^7 - 5^4)^2
Then factor
(3^2(3^3 - 1))^2 * (5^4(5^3 - 1))^2
Simplify
(9*26)^2 * (625*124)^2
E is the answer because there are only 2 factors of 13 in the above expression and E has 4.
(3^5 - 3^2)^2 * (5^7 - 5^4)^2
Then factor
(3^2(3^3 - 1))^2 * (5^4(5^3 - 1))^2
Simplify
(9*26)^2 * (625*124)^2
E is the answer because there are only 2 factors of 13 in the above expression and E has 4.
22 Feb 2013, 01:54
Kudos
Bookmarks
OE is below:
If \(y=\frac{(3^5-3^2)^2}{(5^7-5^4)^{-2}}\), then y is NOT divisible by which of the following?
A. 6^4
B. 62^2
C. 65^2
D. 15^4
E. 52^4
\(y=\frac{(3^5-3^2)^2}{(5^7-5^4)^{-2}}=(3^5-3^2)^2*(5^7-5^4)^2=3^4*(3^3-1)^2*5^8*(5^3-1)^2=3^4*26^2*5^8*124^2=2^6*3^4*5^8*13^2*31^2\).
Now, if you analyze each option you'll see that only \(52^4=2^8*13^4\) is not a factor of \(y\), since the power of 13 in it is higher than the power of 13 in \(y\).
Answer: E.
If \(y=\frac{(3^5-3^2)^2}{(5^7-5^4)^{-2}}\), then y is NOT divisible by which of the following?
A. 6^4
B. 62^2
C. 65^2
D. 15^4
E. 52^4
\(y=\frac{(3^5-3^2)^2}{(5^7-5^4)^{-2}}=(3^5-3^2)^2*(5^7-5^4)^2=3^4*(3^3-1)^2*5^8*(5^3-1)^2=3^4*26^2*5^8*124^2=2^6*3^4*5^8*13^2*31^2\).
Now, if you analyze each option you'll see that only \(52^4=2^8*13^4\) is not a factor of \(y\), since the power of 13 in it is higher than the power of 13 in \(y\).
Answer: E.
