Bunuel wrote:

If \(x\) is a negative integer and \(3 \lt x^2 \lt 36\), then what is the value of twice the maximum possible value of \(x\) minus the minimum possible value of \(x\)?

A. \(-12\)

B. \(-9\)

C. \(-3\)

D. \(1\)

E. \(6\)

Since, x is a negative integer & 3<x<36, It can take the following values, satisfying the mentioned conditions:

-2,-3,-4, and -5.

Now maximum possible value of x = -2 and

Minimum possible value of x = -5.

Now from the question, we have to calculate the following:

2* (Maximum possible Value of x) - (minimum Possible Value of x)

=> 2* (-2) - (-5)

=> -4 + 5

=> 1

Hence D is the answer.