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16 Sep 2014, 01:24
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D
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Difficulty:
45%
(medium)
Question Stats:
64% (01:35) correct
36%
(01:59)
wrong
based on 269
sessions
History
Date
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If \(x\) is a negative integer and \(3 < x^2 < 36\), what is the result of subtracting the minimum possible value of \(x\) from twice the maximum possible value of \(x\)?
A. \(-12\)
B. \(-9\)
C. \(-3\)
D. \(1\)
E. \(6\)
A. \(-12\)
B. \(-9\)
C. \(-3\)
D. \(1\)
E. \(6\)
16 Sep 2014, 01:25
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Official Solution:
If \(x\) is a negative integer and \(3 < x^2 < 36\), what is the result of subtracting the minimum possible value of \(x\) from twice the maximum possible value of \(x\)?
A. \(-12\)
B. \(-9\)
C. \(-3\)
D. \(1\)
E. \(6\)
Given that \(x\) is a negative integer, the possible values for \(x\) are -2, -3, -4, or -5.
Calculating twice the maximum possible value of \(x\), we get \(2*(-2)=-4\).
The minimum possible value for \(x\) is \(-5\).
So, the answer is \(-4-(-5)=1\).
Answer: D
If \(x\) is a negative integer and \(3 < x^2 < 36\), what is the result of subtracting the minimum possible value of \(x\) from twice the maximum possible value of \(x\)?
A. \(-12\)
B. \(-9\)
C. \(-3\)
D. \(1\)
E. \(6\)
Given that \(x\) is a negative integer, the possible values for \(x\) are -2, -3, -4, or -5.
Calculating twice the maximum possible value of \(x\), we get \(2*(-2)=-4\).
The minimum possible value for \(x\) is \(-5\).
So, the answer is \(-4-(-5)=1\).
Answer: D
07 Sep 2018, 11:09
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I think this is a high-quality question and I agree with explanation.
