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Average of largest 5 = -185/5 =-37 So the largest numbers are -41, -39, -37, -35, -33
Now if we consider smallest 5, we have to eliminate last 2 numbers, which are -35 and -33
Notice here that the numbers are equally spaced. So the average of smallest number will just shift 2 place to the left. Avg= -41 Therefore, total = -41*5= -205
Let me ask you a question, which 5 of them are the smallest? Aren't those \(x\), \(x+2\), \(x+4\), \(x+6\) and \(x+8\)? What difference does it make whether x is negative or positive??
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Average of largest 5 = -185/5 =-37 So the largest numbers are -41, -39, -37, -35, -33
Now if we consider smallest 5, we have to eliminate last 2 numbers, which are -35 and -33
Notice here that the numbers are equally spaced. So the average of smallest number will just shift 2 place to the left. Avg= -41 Therefore, total = -41*5= -205
we can have another approach. If we question how many number is added in terms of number line, we will get 12 (largest-lowest) and 8 (2nd largest-2nd lowest). so in total 20 will be added and since all are negative number so the sum will be (-185-20)= -205
here sum is negative right.means Sum of largest number should not be last 5 but a,a+4,........Then answer is -165 Where am I wrong??? I mean clearly a is negative,and in negative numbers smaller is larger.Please reply ??
here sum is negative right.means Sum of largest number should not be last 5 but a,a+4,........Then answer is -165 Where am I wrong??? I mean clearly a is negative,and in negative numbers smaller is larger.Please reply ??
The five largest there are {x+4, x+6, x+8, x+10, x+12} = {-41, -39, -37, -35, -33}. The sum = -185. The five smallest there are {x, x+2, x+4, x+6, x+8} = {-45, -43, -41, -39, -37}. The sum = -205.
here sum is negative right.means Sum of largest number should not be last 5 but a,a+4,........Then answer is -165 Where am I wrong??? I mean clearly a is negative,and in negative numbers smaller is larger.Please reply ??
The five largest there are {x+4, x+6, x+8, x+10, x+12} = {-41, -39, -37, -35, -33}. The sum = -185. The five smallest there are {x, x+2, x+4, x+6, x+8} = {-45, -43, -41, -39, -37}. The sum = -205.
Why I am not getting the same answer if I take the series 2n+1, 2n+3, 2n+5....., 2n+13 Given 5 largest sum, so that will be from 2n+5 to 2n+13 10n+45 = -185 n = 22
Asked - Sum of first five, so that will from 2n+1 to 2n+9 10n + 25 = -195
A set A consists of 7 consecutive odd integers. If the sum of 5 largest integers of set A is -185 what is the sum of the 5 smallest integers of set A?
A. -165 B. -175 C. -195 D. -205 E. -215
Why I am not getting the same answer if I take the series 2n+1, 2n+3, 2n+5....., 2n+13 Given 5 largest sum, so that will be from 2n+5 to 2n+13 10n+45 = -185 n = 22
Asked - Sum of first five, so that will from 2n+1 to 2n+9 10n + 25 = -195
I used easy numbers to plug in and solve. I started at -1,-3,-5,-7,-9,-11,-13. The smallest 5 numbers are -1,-3,-5,-7,-9. The largest 5 numbers are -5,-7,-9,-11,-13. Therefore, -1,-3 and -11,-13 are the only different numbers in those two sets. The difference between those 4 numbers are 20. Then I just add 20 to 185 and I got 205. Done.
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65% (01:51) correct 
Liked your approach !
