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M31-41

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M31-41 [#permalink]

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ABC is a right triangle with right angle at point B. If the ratio of AB to BC is 8 to 15, what is the area of the triangle?



(1) The height from point B to the hypotenuse is 120.

(2) The perimeter of the triangle is 680.
[Reveal] Spoiler: OA

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New post 20 Jun 2015, 11:12
Official Solution:


ABC is a right triangle with right angle at point B. If the ratio of AB to BC is 8 to 15, what is the area of the triangle?

First of all since the ration of AB to BC is \(8x:15x\), then the hypotenuse is \(\sqrt{(8x)^2+(15x)^2}=17x\).

(1) The height from point B to the hypotenuse is 120.

Consider the image below:
Image
The area of a right triangle equals to \(\frac{1}{2}*leg_1*leg_2=\frac{1}{2}**AB*BC\). But the area of a right triangle can also be found by \(\frac{1}{2}*(altitude \ from \ right \ angle)*(hypotenuse)=\frac{1}{2}*BD*AC\).

Equate these expressions:

\(\frac{1}{2}*AB*BC=\frac{1}{2}*BD*AC\);

\(\frac{1}{2}*8x*15x=\frac{1}{2}*120*17x\);

\(120x=120*17\);

\(x=17\).

The area = \(\frac{1}{2}*AB*BC=\frac{1}{2}*8x*15x=60x=60*17\). Sufficient.

(2) The perimeter of the triangle is 680.

The perimeter = \(8x+15x+17x=680\). We can find x, thus we can find the area. Sufficient.


Answer: D
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New post 11 Nov 2016, 21:45
This question could be phrased better in prompt 1) to read the "least distance from B to the hypotenuse". Personally, I interpreted the use of "height" as a descriptor to imply the distance alongside the perimeter (or one of the sides of the triangle rather than the distance measured within the interior). Hence, I selected E for the answer since we didn't know which side it referred to (8x or 15x).

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New post 20 Oct 2017, 15:45
Given statement 1, and the explanation, is it possible to find a different area if the height from point B to the hypotenuse didn't bisect the line into 2 equal parts? I made the assumption that the height could lie on any point of the hypotenuse, not just the center. Am I completely off target here?

Thanks for your help!

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New post 20 Oct 2017, 23:09
Raffio wrote:
Given statement 1, and the explanation, is it possible to find a different area if the height from point B to the hypotenuse didn't bisect the line into 2 equal parts? I made the assumption that the height could lie on any point of the hypotenuse, not just the center. Am I completely off target here?

Thanks for your help!


Hi

How did you assume that the height from the vertex is bisecting the hypotenuse into two equal parts? Thats NOT the case here.

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New post 20 Oct 2017, 23:12
vanceag2016 wrote:
This question could be phrased better in prompt 1) to read the "least distance from B to the hypotenuse". Personally, I interpreted the use of "height" as a descriptor to imply the distance alongside the perimeter (or one of the sides of the triangle rather than the distance measured within the interior). Hence, I selected E for the answer since we didn't know which side it referred to (8x or 15x).


Hi

In a triangle, the word 'height' means perpendicular from any vertex to the opposite side. So, yes two heights here are already AB and BC. But we should know that AB is height from vertex A to opposite side BC, and BC is the height from vertex C to the opposite side AB. The third height will be from vertex B to the opposite side AC, which is what is constructed here in the diagram by Bunuel.

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Re: M31-41   [#permalink] 20 Oct 2017, 23:12
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