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Bunuel
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Bunuel

May i ask how you get from step 3 to step 4 to get x^12=4=2^2 ???

What kind of operation did your perform( Multiplication or division) and how do you arrive at step 4?

Thanks in advance!
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Official Solution:

If \(x > 0\) and \(x^{(3*x^{12})}=4\), what is the value of \(x\) ?

A. \(\sqrt[12]{2}\)
B. \(\sqrt[6]{2}\)
C. \(\sqrt[3]{2}\)
D. \(\sqrt{3}\)
E. \(\sqrt{2}\)


\(x^{(3*x^{12})}=4\);

Take to the fourth power:

\((x^{(3*x^{12})})^4=4^4\);

\(x^{(12*x^{12})}=4^4\);

\((x^{12})^{(x^{12})} =4^4\);

\(x^{12}=4=2^2\);

\(x=(2^2)^{(\frac{1}{12})}\);

\(x=2^{(\frac{1}{6})}\);

\(x=\sqrt[6]{2}\)


Answer: B

Notice that in \((x^{12})^{(x^{12})} =4^4\), both sides have the same form: base raised to the same exponent. On the left, both base and exponent are \(x^{12}\); on the right, both are \(4\). So we equate \(x^{12} = 4\).
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I did not quite understand the solution. Hi, could you please explain why you took the equation to the fourth power in the first step? Sorry if this is obvious. Thank you
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I did not quite understand the solution. Hi, could you please explain why you took the equation to the fourth power in the first step? Sorry if this is obvious. Thank you

We raise both sides to the 4th power to get the same base and exponent form on both sides.

You can check alternative solutions here: https://gmatclub.com/forum/if-x-3-x-12- ... 99492.html
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