Official Solution:
During a Christmas dinner, Timmy enjoyed several candies for dessert. If each candy was either a $0.50 piece or a $0.40 piece, how many $0.50 candies did Timmy have?
Let the number of $0.50 candies be x and the number of $0.40 candies be \(y\). The question asks to find the value of \(x\).
(1) The total cost of the candies Timmy ate was $4.90.>
This implies \(0.5x + 0.4y = 4.9\). Multiplying by 10 gives: \(5x + 4y = 49\). Don't rush to conclude that this is automatically insufficient, since we have one equation and two variables. We should still check because \(x\) and \(y\) must be integers here, so it's possible for the equation to have only one set of \((x, y)\) satisfying it. However, this is not the case for this specific equation. By trial and error, we can find that three sets of \((x, y)\) satisfy \(5x + 4y = 49\): (1, 11), (5, 6), and (9, 1). Not sufficient.
(2) Timmy ate more $0.50 candies than $0.40 candies.
This implies that \(x > y\). Clearly insufficient.
(1)+(2) Given that from (2) \(x > y\), the only pair of \((x, y)\) which satisfies this is (9, 1). Therefore, \(x = 9\). Sufficient.
Answer: C