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Bunuel
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Bunuel
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I have solved it using the below method

even consecutive integers - {2k, 2k+2, 2k+4, 2k+6}
Sum of even consecutive integers - 8k+12

8 consecutive integers set - { 2k+1, 2k+2, 2k+3, 2k+4, 2k+5 2k+6, 2k+7, 2k+8}
Sum of 8 consecutive integers - 16k + 36

now as per the question
8k +12 = 16k +36
k = -3

Now difference between the sums of non - identical elements in the two sets
2k+1+2k+2+2k+3+2k+4 + 2k+5+2k+6+2k+7+2k+8 - ( 2k+2k+2+2k+4+2k+6)
2k+1+2k+2+2k+3+2k+4+2k+5 2k+6+2k+7+2k+8 - 2k-2k-2-2k-4-2k-6
2k+1+2k+3+2k+5+2k+7+8
8k+24
8(-3) +24 = 0


Bunuel
Quote:
If the sum of four consecutive even integers is equal to the sum of eight consecutive integers, what is the difference between the sums of the non-identical elements in the two sets?

A. 0
B. 2
C. 4
D. 6
E. 8
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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This is a great question that’s helpful for learning.
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i reached till here using
y, y+2, y+4, y+6 = x, x+1, x+2, x+3, x+4, x+5, x+6, x+7
4y + 12 = 8x + 16
y = 2x + 4 ....got stuck what next maybe
x = 1, i get y = 6
and one sample values I would have
6, 8, 10, 12 = 1, 2, 3, 4, 5, 6, 7, 8
and further acc to question i could have solved....darn it :(
Anugmat740
Sum of First 8 integers starting from 1 to 8 = 36

Sum of Four even integers whose sum is equal to 36.
(To get these even integers, 36/4=9. Take even integers close to 9 to get sum as 36. We get (6,8,10,12)

Common integers in these two sets are 6 and 8.

Sum of remaining integers from 1-8 (excluding 6 and 8) = 36-14 = 22

Sum of even integers (6,8,10,12) (excluding common terms (6 and 8)) we get = 36-14 =22

The difference between the sums of the non-identical elements in the two sets= 22-22 =0­
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Given:
Sum of 4 consecutive even numbers = sum of 8 consecutive numbers
S(4 even numbers) = S(8 consecutive numbers)
Sn = n/2(2a+(n-1)d)
putting n =4 and d=2 for even numbers
and n=8 and d=1 for consecutive numbers
4/2(2a+3(2)) = 8/2(2a+7(1))
==> a=-4
So our sets are -4,-2,0,2
and -4,-3,-2,-1,0,1,2 & 3
Difference between the sums of the non-identical elements in the two sets:
Sum of non-identical elements: -3,-1,1,3 = 0
So our the difference is 0
Option A
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