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Above analysis may not hold true in case of fractions. Question does not say x and y are integers. So we cannot rule out the possibility of fractions.

1 Example:
x = 1/4 y= 1/2

x^2 = 1/16
xy = 1/8

here, x^2<xy

2 Example
x = 4 y= 2

x^2 = 16
xy = 4

here, x^2>xy

I think the solution should be E

Let me know if i am missing out something
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KomalT
Above analysis may not hold true in case of fractions. Question does not say x and y are integers. So we cannot rule out the possibility of fractions.

1 Example:
x = 1/4 y= 1/2

x^2 = 1/16
xy = 1/8

here, x^2<xy

2 Example
x = 4 y= 2

x^2 = 16
xy = 4

here, x^2>xy

I think the solution should be E

Let me know if i am missing out something

But in your first example, 1/4 < 1/2, which contradicts the stem.
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given x>y

If x =2 and y =1, then x2 = 4 and xy = 2.

Thus x2>xy (TRUE FOR ALL POSITIVE NUMBERS SUCH THAT X>Y). SO THE ANSWER IS YES

But if x = -1 & y =-2, then x2 = 1 and xy = 2.

Thus x2<xy. SO THE ANSWER IS NO.


So how is Statement 1 sufficient ????


Please help me out
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xyzzy94
given x>y

If x =2 and y =1, then x2 = 4 and xy = 2.

Thus x2>xy (TRUE FOR ALL POSITIVE NUMBERS SUCH THAT X>Y). SO THE ANSWER IS YES

But if x = -1 & y =-2, then x2 = 1 and xy = 2.

Thus x2<xy. SO THE ANSWER IS NO.


So how is Statement 1 sufficient ????


Please help me out
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Notice that (1) says that x > 0.
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I think this is a high-quality question and I agree with explanation.
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