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M70-02

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Math Expert
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Joined: 02 Sep 2009
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M70-02  [#permalink]

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New post 03 Sep 2018, 01:56
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

73% (01:48) correct 27% (02:22) wrong based on 11 sessions

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Math Expert
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Re M70-02  [#permalink]

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New post 03 Sep 2018, 01:56
Official Solution:


We’ll go for PRECISE because all the information we need is in the question.

(1) If \(x\) is a positive integer under 20, \(x + 7\) must be a positive integer under 27. The integers in this range that have a remainder of 1 when divided by 5 are those that are larger by 1 than a multiple of 5: these are the numbers 1, 6, 11, 16, 21, and 26 – meaning that x can be 4, 9, 14 or 19. But which one? (A) and (D) are eliminated.

(2) The numbers under 20 that have a remainder of 2 when divided by 4 are larger by 2 than a multiple of 4: 2, 6, 10, 14, and 18, so we don’t have a definite result. (B) is eliminated. Combining (1) and (2) leaves only 14 as a possible answer. Enough! (E) is eliminated.


Answer: C
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Re: M70-02  [#permalink]

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New post 03 Dec 2018, 07:04
Why 14?
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Re: M70-02   [#permalink] 03 Dec 2018, 07:04
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M70-02

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