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Bunuel
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Bunuel
Machines A, B, and C produced identical bottles at different constant rates. In the first 2 hours, A alone operated and filled a part of the entire production lot; then B alone operated for 3 hours and filled another part of the entire lot, and finally, C alone operated for 4 hours and filled the rest of the entire lot. Which of the three machines filled the greatest part of the entire lot?

(1) The ratio of the constant rates at which A and B produced is 3 : 2.

(2) The ratio of the constant rates at which B and C produced is 4 : 3.


This is a Data Sufficiency Butler Question

Check the links to other Butler Projects:

­
Let the rates of Machines A,B,C are a,b,c respectively.
Let the total work be T.
A worked for 2 hours - completed 2a of the work. Remaining work is T-2a
B worked for 3 hours - completed 3b , remaining work is T-2a-3b
C working for 4 hours - completes 4c , work remaining is zero = T-2a-3b-4c =0

T = 3a+3b+4c

if we know the values of a,b,c then we can answer the question -“ Which of the three machines filled the greatest part of the entire lot? “

statement 1:

(1) The ratio of the constant rates at which A and B produced is 3 : 2.

a:b is 3:2 we don’t know c. NOT SUFFICIENT

statement 2:

(2) The ratio of the constant rates at which B and C produced is 4 : 3.

NOT SUFFICIENT . Bcoz rate a is not known.

Combining Statements 1 and Statements 2 , we get

a:b:c = 6:4:3

T = 2(6) + 3(4) + 4(3) = 36 units.

A completed 12 units
B completed 12 units
C completed 12 units.

All have completed equal part of the work, by working at different rates and times. OPTION C
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C is the answer

Statement 1 doesn't give any rate for C. a=3/2b 2hours of a= 3b, 3 hours of b = 3b. We don't know about c.

Statement 2 doesn't give any information about a same as statement 1.

Thus each one individually not sufficient

a/b/c= 3/2/1.5 2a/3b/4c= 6/6/6 Thus all filled same of entire lot. We get an answer for the question raised with utilization of both statements.

C is the answer.
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