Marcia took a trip consisting of three segments at three different speeds: she drove a distance of (5D) at a speed of (2v), then a distance of (4D) at a speed of (3v), then a distance of D at a speed of (6v). In terms of D & v, what was the total time of Marcia’s trip?
(A) 4D/v
(B) 4v/D
(C) (10D)/(11v)
(D) (10v)/(11D)
(E) (11D)/(10v)Trip distance: 5D.............4D................DVelocity :2v...............3v................6vTime :5D/2v...........4D/3v..........D/6vSo, total time of Marcia's Trip = 5D/2v + 4D/3v + D/6v
= 15D/6v + 8D/6v + D/6v
= 24D/6v
= 4 D/v
Answer (A)
Alternative SolutionLet D = 100 and v= 50.
So,
D/v = 2Trip distance:500...........400...........100Velocity :100...........150............300Time [= Trip Distance/Velocity]:5........... 8/3............1/3So, Total Trip Time = 5 + 8/3 + 1/3
= 24/3
= 8..................(1)
Back solving, starting from (C), plugging (D/v) as 2 and evaluating each choice to see which one equals 8 [as calculated in (1)]
(A) 4D/v ............................. 4* 2 =8.....
matches the answer (1) calculated above.
(B) 4v/D . ........................... eliminate as v/D is not time
(C) (10D)/(11v)................... (10/11)*2....definitely not 8, hence eliminate.
(D) (10v)/(11D)
(E) (11D)/(10v)[/color]
Answer (A).