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Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 choc

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Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 choc  [#permalink]

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New post 24 Sep 2018, 11:29
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89% (00:44) correct 11% (01:26) wrong based on 45 sessions

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Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 chocolate candies, and 20 banana chips. She picks one item from the bag at random. What is the probability that she picks either a chocolate candy or a banana chip?

a. 1/50

b. 1/10

c. 1/5

d. 3/10

e. 7/10

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Re: Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 choc  [#permalink]

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New post 24 Sep 2018, 22:44
AkshdeepS wrote:
Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 chocolate candies, and 20 banana chips. She picks one item from the bag at random. What is the probability that she picks either a chocolate candy or a banana chip?

a. 1/50

b. 1/10

c. 1/5

d. 3/10

e. 7/10



pretty straightforward..

total ways ONE item can picked up = ( 30+40+10+20)=100
ways a chocolate candy and banana chips can be picked..
chocolate candy - 10 and banana chips - 20, so total - 30

probability - \(\frac{30}{100} = \frac{3}{10}\)

D
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Re: Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 choc  [#permalink]

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New post 25 Sep 2018, 02:06
Probability of picking Choc. candies = 10/100 = 1/10
Probability of picking Bana. Chips = 20/100 = 1/5

Probability that she picks either a chocolate candy or a banana chip = 1/10 +1/5 = 3/10

Hence D
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Re: Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 choc  [#permalink]

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New post 27 Sep 2018, 17:23
AkshdeepS wrote:
Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 chocolate candies, and 20 banana chips. She picks one item from the bag at random. What is the probability that she picks either a chocolate candy or a banana chip?

a. 1/50

b. 1/10

c. 1/5

d. 3/10

e. 7/10


There are 100 items in the bag, including 10 chocolate candies and 20 banana chips. We add the probabilities of the individual items to obtain the probability of picking either a chocolate candy (C) or a banana chip (B).

P(C or B) = 10/100 + 20/100 = 30/100 = 3/10

Answer: D
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Re: Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 choc &nbs [#permalink] 27 Sep 2018, 17:23
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