[GMAT math practice question]
Reading from the right, how many consecutive zeros, starting with the units digit, appear in 29!?
A. 5
B. 6
C. 7
D. 8
E. 9
=>
To find the number of 0’s ending 29!, we need to count the numbers of 2’s and 5’s in the prime factorization of 29!.
Since the number 2’s is greater than the number of 5’s, we only need to count the number of 5’s in the prime factorization of 29!.
The factors of 5 are contributed by 5, 10, 15, 20 and 25. Each of 5, 10, 15 and 20 contributes one 5, while 25 contributes two 5s to the prime factorization.
Thus, there are 6 copies of 5 in the prime factorization of 29!, giving rise to 6 consecutive 0’s at the end of 29!.
Therefore, the answer is B.
Answer : B
Note: The actual value of 29! is 8841761993739701954543616000000.