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Que: If ‘p’ and ‘q’ are integers, what is the value of p?

(1) \(\frac{q}{p} = \frac{1}{3}.\)

(2) \(q < 0 and p < 0.\)
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Que: If ‘p’ and ‘q’ are integers, what is the value of p?

(1) \(\frac{q}{p} = \frac{1}{3}.\)

(2) \(q < 0\) and \(p < 0.\)


Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find the value of p.

Follow the second and the third step: From the original condition, we have 2 variables (p and q). To match the number of variables with the number of equations, we need 2 equations. Since conditions (1) and (2) will provide 1 equation each, C would most likely be the answer.

Recall 3- Principles and Choose C as the most likely answer.

Let’s look at both conditions together.

Condition (1) tells us that \(\frac{q}{p} = \frac{1}{3}\) , and Condition (2) tells us that p < 0 and q < 0.

Number of possible cases for \(\frac{q}{p}\) such that ratio is 1:3 are

=> q = -1 and p = -3 (q < 0, p < 0)

=> q = -2 and p = -6 (q < 0, p < 0)

=> q = -6 and p = -18 (q < 0, p < 0)

And so on…

The answer is not a unique value; both conditions combined are not sufficient according to Common Mistake Type 2 which states that the answer should be a unique value.

Both conditions together are not sufficient.

Therefore, E is the correct answer.

Answer: E
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Que: The cost of a certain phone call was $3 for the first 4 minutes and $0.20 for each additional minute after the first 4 minutes. Did the phone call last longer than 8 minutes?

(1) The cost of the phone call was greater than $5.00.
(2) The cost of the phone call was less than $5.00.
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Que: The cost of a certain phone call was $3 for the first 4 minutes and $0.20 for each additional minute after the first 4 minutes. Did the phone call last longer than 8 minutes?

(1) The cost of the phone call was greater than $5.00.
(2) The cost of the phone call was less than $5.00.



Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find whether the call cost longer than 8 minutes.

A 8- minute call will cost as: cost of 4 minutes + additional cost of 4 minutes = $3 + 4($0.20) = $3.80

We have to find did the call cost more than $3.80?

Condition (1) tells us that the cost of the phone call was more than $5.00.

This implies the cost of the call will always be greater than $3.80 - YES

The answer is a unique YES; condition (1) alone is sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.

Condition (2) tells us that the cost of the phone call was less than $5.00.

=> If call cost = $2.70, then we get NO as an answer

=> But If call cost = $4.00, then we get YES as an answer

The answer is not a unique YES or a NO; condition (2) alone is not sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.

Condition (1) alone is sufficient.

Therefore, A is the correct answer.

Answer: A
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Que: What is the standard deviation of four numbers a, b, c, and d?

(1) Sum of a, b, c, and d is 24.
(2) Sum of squares of a, b, c, and d is 240.
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Que: What is the standard deviation of four numbers a, b, c, and d?

(1) Sum of a, b, c, and d is 24.
(2) Sum of squares of a, b, c, and d is 240.



Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find ‘S.D. of a, b, c, and d.

Let A = mean of square numbers

B = square of mean of numbers

S.D. = \(\sqrt {(A) - (B)}\)


Follow the second and the third step: From the original condition, we have 4 variables (a, b, c, and d). To match the number of variables with the number of equations, we need 4 equations. Since conditions (1) and (2) will provide 1 equation each, E would most likely be the answer.

Recall 3- Principles and Choose E as the most likely answer. Let’s look at both conditions together.

Condition (1) tells us that the sum is 24.

Condition (2) tells us that the sum is 240.

From 1st: Mean = 6 and square of mean = \(36\)

From 2nd: Mean of squares of numbers = \(\frac{240}{4} = 60\)

A = mean of square numbers = 60

B = square of mean of numbers = 36

S.D. = \(\sqrt {(60) - (36) = 24 ≈ 25} = 5\)


The answer is unique, so the conditions combined are sufficient according to Common Mistake Type 2 which states that the answer should be a unique value.

Both conditions together are sufficient.

Therefore, C is the correct answer.

Answer: C
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Que: If the product of two distinct integers’ p and q is 50, what is q?

(1) q is an even integer.
(2) p > q.
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Que: If the product of two distinct integers’ p and q is 50, what is q?

(1) q is an even integer.
(2) p > q.


Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find the value of q – where ‘p’ and ‘q’ are integers and p * q = 50.

Follow the second and the third step: From the original condition, we have 2 variables (p, and q) and 1 equation (p * q = 50). To match the number of variables with the number of equations, we need 1 more equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.
Recall 3- Principles and Choose D as the most likely answer. Let’s look at each condition.

Condition (1) tells us that q is an even integer.

For p * q = 50, where ‘q’ is even - we can have the following possible combinations

=> p = 5 and q = 10 – q is even

=> p = -5 and q = -10 – q is even

=> p = 25 and q = 2 – q is even

=> p = -25 and q = -2 – q is even

The answer is not unique, so Condition (1) alone is not sufficient according to Common Mistake Type 2 which states that the answer should be a unique value.

Condition (2) tells us that p > q.

For p * q = 50, where ‘p > q’ - we can have following possible combinations

=> p = 25 and q = 2 – p > q

=> p = 10 and q = 5 – p > q

The answer is not unique, so Condition (2) alone is not sufficient according to Common Mistake Type 2 which states that the answer should be a unique value.

Let’s look at both conditions combined:

For p * q = 50, where ‘p > q’ and ‘q’ is even - we can have the following possible combinations

=> p = 25 and q = 2 – p > q and ‘q’ is even

=> p=-5 and q=-10 - p > q and ‘q’ is even

The answer is not unique, so conditions combined are not sufficient according to Common Mistake Type 2 which states that the answer should be a unique value.

Both conditions together are not sufficient.

Therefore, E is the correct answer.

Answer: E
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Que: Is ‘a’ an integer?

(1) \(a^3\) is an integer.
(2) \(6a\) is an integer.
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Que: Is ‘a’ an integer?

(1) \(a^3\) is an integer.
(2) \(6a\) is an integer.


Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find whether ‘a’ is an integer.

Follow the second and the third step: From the original condition, we have 1 variable (a). To match the number of variables with the number of equations, we need 1 equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.

Recall 3- Principles and Choose D as the most likely answer. Let’s look at each condition separately.

Condition (1) tells us that the \(a^3\) is an integer.

=> If \(a^3 = 8\), then a = 2. YES

=> But if \(a^3 = 16\), then a is not an integer. NO

The answer is not a unique YES or a NO, so Condition (1) alone is not sufficient according to Common Mistake Type 1 which states that the answer should be a unique value.

Condition (2) tells us that the 6a is an integer.

=> If a = 10, then 6a = 10 * 6 = 60.

=> But if a = 7.5, then 6a = 6 * 7.5 = 45.

The answer is not a unique YES or a NO, so Condition (2) alone is not sufficient according to Common Mistake Type 1 which states that the answer should be a unique value.


Let’s look at both conditions combined:

=> If \(a^3 = 8\), then a = 2 and then 6a = 6 * 2 = 12 is an integer – YES

=> If \(a^3 = 1\), then a = 1 and then 6a = 6 * 1 = 6 is an integer – YES

=> But if, \(a^3 = 16\), then a = 2.52 and then 4a = 6 * 2.52 = is not an integer

Only if ‘a’ is an integer then, \(a^3\) and 6a will be an integer.

The answer is a unique value YES; both conditions combined are sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.

Both conditions together are sufficient.

Therefore, C is the correct answer.

Answer: C
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Que: If |x - 3| > 1, what is the value of x?

(1) \(x > -2\)
(2) \(x^2 - 4x + 3 = 0\)
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Que: If |x - 3| > 1, what is the value of x?

(1) \(x > -2\)
(2) \(x^2 - 4x + 3 = 0\)


Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously. [Watch lessons on our website to master these 3 steps]

Step 1 of the Variable Approach: Modifying and rechecking the original condition and the question.

We have to find the value of ‘x’ when is |x - 3| > 1.

Since, |x - 3| < 1, then x - 3 < -1 or x – 3 > 1.

=> If x - 3 < -1, then x < 2

=> If x - 3 > 1, then x > 4

We have to find the value of x.

Follow the second and the third step: From the original condition, we have 1 variable (x). To match the number of variables with the number of equations, we need 1 equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.

Recall 3- Principles and Choose D as the most likely answer. Let’s look at each condition separately.

Thus, look at condition (1) that tells us that x > -2.

=> x = 5, 6,….

The answer is not unique; so condition (1) alone is not sufficient according to Common Mistake Type 2 which states that the answer should be a unique value.

Condition (2) tells us that \(x^2 - 4x + 3 = 0\)

=> \(x^2 - 4x + 3 = 0\)

=> (x - 1) (x - 3) = 0

=> x = 3 or 1

=> x= only 1 (since x<2 or x>4)

The answer is unique; so condition (2) alone is sufficient according to Common Mistake Type 2 which states that the answer should be a unique value.

Condition (2) alone is sufficient.

Therefore, B is the correct answer.

Answer: B
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Que: When P is divided by 2, is the remainder 1?

(1) \((-1)^{P+2} = 1. \)
(2) P is a prime.
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Que: When P is divided by 2, is the remainder 1?

(1) \((-1)^{P+2} = 1. \)
(2) P is a prime.


Solution: Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find ‘Is remainder 1 when P is divided by 2.

Follow the second and the third step: From the original condition, we have 1 variable (P). To match the number of variables with the number of equations, we need 1 equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.

Recall 3- Principles and Choose D as the most likely answer.

Let’s look at both conditions combined together.

Condition (1) tells us that \((-1)^{P+2} = 1.\)

=> \((-1)^ {even}\) gives us 1.

Hence, P + 2 = even. Therefore, P = even – 2 = even – even = even.

If P is even, then the remainder, when P divided by 2, is 0. It is not 1.

The answer is unique NO; condition (1) alone is sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.


Condition (2) tells us that P is a prime.

=> If P = 2 remainder is 0 – is remainder 1 - NO

=> If P = any other prime number which is all odd then the remainder is 1 –YES

The answer is not a unique YES or a NO; both conditions combined are not sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.

Condition (1) alone is not sufficient.

Therefore, A is the correct answer.

Answer: A
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Que: If a and b are positive integers, is ab a multiple of 18?

(1) a is a multiple of 6.
(2) b is a multiple of a.
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Que: If a and b are positive integers, is ab a multiple of 18?

(1) a is a multiple of 6.
(2) b is a multiple of a.



Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find whether ab is a multiple of 18 – where ‘a’ and ‘b’ are positive integers.

=> ab = 18n – where ‘n’ must be an integer

Follow the second and the third step: From the original condition, we have 2 variables (a and b). To match the number of variables with the number of equations, we need 2 equations. Since conditions (1) and (2) will provide 1 equation each, C would most likely be the answer.

Recall 3- Principles and Choose C as the most likely answer. Let’s look at both conditions combined together.

Condition (1) tells us that a is a multiple of 6.

=> a = 6m ; where m is any integer

Condition (2) tells us that b is a multiple of a.

=> b = ap=6mp ; where p is any integer

=> From them, we can determine whether ab is a multiple of 18, since \(ab=(6m)(6mp)=36(m^2p)=18(2m^2p).\)

The answer is a unique YES; both conditions combined are sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.


Both conditions together are sufficient.

Therefore, C is the correct answer.

Answer: C
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Que: Is pq < 5?

(1) p > - 4 and q < 1.
(2) p < −2 and q > −4.
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