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Math Revolution GMAT Instructor
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08 Mar 2019, 02:37
[GMAT math practice question] If \(n\) is a positive integer, is \(n\) a prime number? 1) \(n\) is the least factor of \(77\) greater than \(1\) 2) \(n\) has exactly two factors
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10 Mar 2019, 18:18
MathRevolution wrote: [GMAT math practice question]
(statistics) Is the average (arithmetic mean) of \(x, y,\) and \(z\) equal to their median?
1) \(y\) is the average (arithmetic mean) of \(x, y,\) and \(z\) 2) \(z = 2y  x\) => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. If data are symmetric, then the average and the median of the data are the same. Condition 1): If \(y\) is the mean of \(x, y\) and \(z\), then \(x, y, z\) are symmetric. To see this note that \(\frac{( x + y + z )}{3} = y\) implies that \(y = \frac{( x + z )}{2}\). So, \(2y = x + z\) and \(y – x = z – y,\) which means that \(x, y, z\) are symmetric. Condition 1) is sufficient. Condition 2): \(z = 2y – x\) is equivalent to \(y – x = z – y\), which is equivalent to condition 1). Condition 2) is sufficient. FYI, Tip 1) of the VA method states that D is most likely to be the answer if conditions 1) and 2) provide the same information. Therefore, D is the answer. Answer: D
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10 Mar 2019, 18:20
MathRevolution wrote: [GMAT math practice question]
If \(n\) is a positive integer, is \(n\) a prime number?
1) \(n\) is the least factor of \(77\) greater than \(1\) 2) \(n\) has exactly two factors => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Since we have \(1\) variable (\(n\)) and \(0\) equations, D is most likely to be the answer. So, we should consider each condition on its own first. Condition 1) The factors of \(77\) are \(1, 7, 11\) and \(77\). We have \(n = 7\) since the least factor of \(77\) other than \(1\) is \(7\). Condition 1) is sufficient. Condition 2) \(n\) is a prime number, by definition, since it has exactly two factors. Condition 2) is sufficient. Therefore, D is the answer. Answer: D If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
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11 Mar 2019, 18:11
[GMAT math practice question] (algebra) \(x\) and \(y\) are integers. If \(y≠3\), is \(x=4\)? \(1) x+y=7\) \(2) x^2+y^2=25\)
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12 Mar 2019, 00:44
[GMAT math practice question] (exponent) If \(x\) and \(y\) are positive integers, \(\frac{x}{y}\)=? \(1) 2^{x+y}3^{xy}=72\) \(2) 2^x3^y=12\)
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13 Mar 2019, 00:53
MathRevolution wrote: [GMAT math practice question]
(algebra) \(x\) and \(y\) are integers. If \(y≠3\), is \(x=4\)?
\(1) x+y=7\) \(2) x^2+y^2=25\) => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Since we have \(2\) variables (\(x\) and \(y\)) and \(0\) equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2): Since \(y = 7 – x, x^2+y^2=25\) is equivalent to \(x^2+(7x)^2=25\) or \(2x^2 – 14x + 24 = 0.\) This factors as \(2(x^2 – 7x + 12) = 0\) or \(2(x3)(x4) = 0.\) So, \(x = 3\) and \(y = 4\), or \(x = 4\) and \(y = 3\). Since \(y ≠3\), we must have \(x = 3\) and \(x\) can’t be \(4\). Since ‘no’ is also a unique answer by CMT (Common Mistake Type) 1, both conditions are sufficient, when used together. Since this question is an integer question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B. Condition 1) Since \(y = 7 – x ≠ 3, x\) can’t be \(4\). So, we have a unique answer, which is “no”. Since ‘no’ is also a unique answer by CMT (Common Mistake Type) 1, condition 1) is sufficient. Condition 2) If \(x = 4\) and \(y = 3\), then \(x^2+y2 = 25\), and the answer is “yes”. If \(x = 3\) and \(y = 4,\) then \(x^2+y2 = 25\), and the answer is “no”. Thus, condition 2) is not sufficient, since it does not yield a unique solution. Therefore, A is the answer. Answer: A Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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13 Mar 2019, 00:53
[GMAT math practice question] If \(xyz≠0\), is \(x^3y^4z^5>0?\) \(1) xz>0\) \(2) xyz>0\)
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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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13 Mar 2019, 09:27
MathRevolution wrote: [GMAT math practice question]
If \(xyz≠0\), is \(x^3y^4z^5>0?\)
\(1) xz>0\) \(2) xyz>0\) Given: xyz ≠ 0 Target question: Is x³y⁴z⁵ > 0? This is a great candidate for rephrasing the target question. Since we know that x² must be POSITIVE, we can safely take the inequality x³y⁴z⁵ > 0 and divide both sides by x² to get: xy⁴z⁵ > 0 Similarly, since y⁴ is POSITIVE, we can safely divide both sides by y⁴ to get: xz⁵ > 0 Finally, since z⁴ is POSITIVE, we can safely divide both sides by z⁴ to get: xz > 0REPHRASED target question: Is xz > 0? Statement 1: xz > 0 PERFECT! The answer to the REPHRASED target question is YES, xz IS greater than 0Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT Statement 2: xyz > 0There are several values of x, y and z that satisfy statement 2. Here are two: Case a: x = 1, y = 1 and z = 1. In this case, xz = (1)(1) = 1. So, the answer to the REPHRASED target question is YES, xz IS greater than 0Case b: x = 1, y = 1 and z = 1. In this case, xz = (1)(1) = 1. So, the answer to the REPHRASED target question is NO, xz is NOT greater than 0Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT Answer: A Cheers, Brent
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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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13 Mar 2019, 09:39
How many DS questions will be there in the test?



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13 Mar 2019, 09:42
AjjayKannan wrote: How many DS questions will be there in the test? There is no actual count on how much DS questons one might face on the test day. It might range from 1315. Totally depends.
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14 Mar 2019, 01:46
MathRevolution wrote: [GMAT math practice question]
(exponent) If \(x\) and \(y\) are positive integers, \(\frac{x}{y}\)=?
\(1) 2^{x+y}3^{xy}=72\) \(2) 2^x3^y=12\) => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. Condition 2) tells us that \(2^x3^y=12 = 2^23^1\) and \(x = 2, y = 1.\) Thus \(\frac{x}{y} = \frac{2}{1} = 2\), and condition 2) is sufficient. Condition 1) \(2^{x+y}3^{xy}=72 = 2^33^2\) yields the equations \(x+y=3\) and \(xy=2\). So, \(x = 1\) and \(y = 2, or x =2\) and \(y = 1\). Thus, \(\frac{x}{y} = \frac{1}{2}\) or \(\frac{x}{y} = \frac{2}{1} = 2\). Condition 1) is not sufficient since it does not yield a unique solution. Therefore, B is the answer. Answer: B
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14 Mar 2019, 01:48
[GMAT math practice question] (function) If \(f(x)=ax^2+bx+c,\) where \(a, b\) and \(c\) are integers, is \(b=0\)? \(1) f(49)=f(49)=0\) \(2) f(0)f(49)=0\)
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15 Mar 2019, 00:07
MathRevolution wrote: [GMAT math practice question]
If \(xyz≠0\), is \(x^3y^4z^5>0?\)
\(1) xz>0\) \(2) xyz>0\) => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. Asking if \(x^3y^4z^5>0\) is equivalent to asking if \(xz > 0\) since we can ignore even exponents in inequalities. Thus, condition 1) is sufficient. Condition 2) If \(x = 1, y = 1\) and \(z = 1\), then \(x^3y^4z^5>0\), and the answer is “yes”. If \(x = 1, y = 1\) and \(z = 1\), then \(x^3y^4z^5<0\), and the answer is “no”. Condition 2) is not sufficient since it does not yield a unique answer. Therefore, A is the answer. Answer: A
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15 Mar 2019, 00:08
[GMAT math practice question] (function) The point (\(p,q\)) lies in which quadrant of the \(xy\) plane? 1) (\(p+1, q\)) lies in the 2nd quadrant 2) (\(q1, p\)) lies in the 4th quadrant
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Math Revolution DS Expert  Ask Me Anything about GMAT DS
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Updated on: 03 Jul 2019, 09:38
MathRevolution wrote: [GMAT math practice question]
(function) If \(f(x)=ax^2+bx+c,\) where \(a, b\) and \(c\) are integers, is \(b=0\)?
\(1) f(49)=f(49)=0\) \(2) f(0)f(49)=0\) => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. In order to have \(b =0, f(x)\) must be symmetric about the yaxis. Thus, condition 1) is sufficient. By the factor theorem, condition 1) tells us that \(f(x) = a(x49)(x+49) = a(x^2 – 49^2) = ax^2 – 49^2a\) and \(b = 0\). It is sufficient. Condition 2) If \(f(0)f(49) = 0\) then either \(f(0)= 0\) or \(f(49) = 0\). Note that \(f(0) = c\). If \(a = 1, b = 0\) and \(c = 0\), then \(f(0) = 0,\) so \(f(0)f(49) = 0\), and the answer is ‘yes’. If \(a = 1, b = 1\) and \(c = 0\), then \(f(0) = 0\), so \(f(0)f(49) = 0\), and the answer is ‘no’. Thus, condition 2) is not sufficient, since it does not yield a unique solution. Therefore, A is the answer. Answer: A
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17 Mar 2019, 18:18
MathRevolution wrote: [GMAT math practice question]
(function) The point (\(p,q\)) lies in which quadrant of the \(xy\) plane?
1) (\(p+1, q\)) lies in the 2nd quadrant 2) (\(q1, p\)) lies in the 4th quadrant => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. Condition 1) tells us that \(p + 1 < 0\) and \(q > 0\), which is equivalent to \(p < 1 < 0\) and \(q > 0\). Thus, (\(p, q\)) is in the 2nd quadrant. Condition 1) is sufficient. Condition 2) tells us that \(q  1 > 0\) and \(p < 0\), which is equivalent to \(p < 0\) and \(q > 1 > 0\). Thus, (\(p, q\)) is in the 2nd quadrant. Condition 2) is sufficient. Therefore, D is the answer. Answer: D FYI, Tip 1) of the VA method states that D is most likely to be the answer if conditions 1) and 2) provide the same information.
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18 Mar 2019, 00:39
[GMAT math practice question] (number properties) Is \(\sqrt{15n}\) an integer? 1) \(n\) is a multiple of \(3\) 2) \(n\) is the square of an integer
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19 Mar 2019, 00:35
[GMAT math practice question] (absolute value) \(xy=?\) \(1) (x2)^2 = y3\) \(2) x2 + \sqrt{y3} =0\)
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19 Mar 2019, 10:32
(integer) [x] is the greatest integer less than or equal to x, is x[x]>0?
1) x is positive 2) x is not integer



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19 Mar 2019, 10:33
(ratio) All of the households used a total of x watts for 24 hours and one household used y watts per hour. What is the total number of all the households, in terms of x and y?
A. x/y B. 24x/y C. x/24y D. 24xy E. 24/xy




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