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22 Jun 2011, 07:28
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How would you go about reducing this to solve.....
15^x + 15^(x+1) = 15^y * (4^y)
(fifteen to the x) added to (15 to the x plus 1) = (15 to the y) MULTIPLIED BY (4 to the y)
Answer is 2
15^x + 15^(x+1) = 15^y * (4^y)
(fifteen to the x) added to (15 to the x plus 1) = (15 to the y) MULTIPLIED BY (4 to the y)
Answer is 2
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22 Jun 2011, 07:34
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shs0145
15^x+ 15^x*15( base same powers were added) = 15^y*4^y
take 15 ^x out
15^x(1+15) = 15^y*4^y
15^x*16 = 15^y*4^y
15^x*4^2= 15^y*4^y
hence Y = 2
22 Jun 2011, 07:36
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LHS = \(15^x + 15^(x+1)\) = \(15^x(1+15)\) = 16*\(15^x\) = \(4^2*15^x\)
therefore, \(4^2*15^x\) = \(15^y*4^y\)
from the above since the bases are the same, we can say x=y=2.
therefore, \(4^2*15^x\) = \(15^y*4^y\)
from the above since the bases are the same, we can say x=y=2.
