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Your question is kinda Incomplete. But if asking for solving module. lx-2l = l2x-3l +/- (x - 2) = +/- (2x-3) you have to take either negative on one side or leave both side as positive as all possible case will give same solution as both of them Case 1: (x - 2) = (2x-3) -2+3 = 2x - x x = 1 or, Case 2: (x - 2) = -(2x-3) x+2x = 3+2 3x = 5 x = 5/3 Hopefully this helps
Your question is kinda Incomplete. But if asking for solving module. lx-2l = l2x-3l +/- (x - 2) = +/- (2x-3) you have to take either negative on one side or leave both side as positive as all possible case will give same solution as both of them Case 1: (x - 2) = (2x-3) -2+3 = 2x - x x = 1 or, Case 2: (x - 2) = -(2x-3) x+2x = 3+2 3x = 5 x = 5/3 Hopefully this helps
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This is correct, we need more information if answer has to be specific value of x