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n is an integer chosen at random from the set {5, 7, 9, 11 } p is

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n is an integer chosen at random from the set {5, 7, 9, 11 } p is [#permalink]

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New post 18 May 2016, 00:47
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n is an integer chosen at random from the set

{5, 7, 9, 11 }

p is chosen at random from the set
{2, 6, 10, 14, 18}

What is the probability that n + p = 23 ?

A. 0.1
B. 0.2
C. 0.25
D. 0.3
E. 0.4
[Reveal] Spoiler: OA

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Re: n is an integer chosen at random from the set {5, 7, 9, 11 } p is [#permalink]

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New post 18 May 2016, 03:32
It can be (5,18) or (9,14)
Prob of 5,18 is ( 4*5/2) =10

Similarly for 9,14 is 10
So 10+10 / 100 = 0.2.
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Re: n is an integer chosen at random from the set {5, 7, 9, 11 } p is [#permalink]

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New post 18 May 2016, 17:03
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Hi everybody.
Set N: there is 4 ways to chose a number
Set P: there is 5 ways to chose a number
so total outcome is 4*5 = 20 which is represent 20 pairs of number
now we have 2 pairs can give us 23 which are (5,8) and (9,14) .
2/20 = 0.1


I dont know if it the right solution or no t.... will see
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Re: n is an integer chosen at random from the set {5, 7, 9, 11 } p is [#permalink]

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New post 19 May 2016, 06:23
n {5, 7, 9, 11 }

p {2, 6, 10, 14, 18}

n + p = 23

Statement 1 : Let us start with n=5 What would be P for the sum of n+p to be 23, it has to be 18
n = 7 P should be 17 but its not the part of set P, so such a combination is not possible.
n = 9 P should be 14

(5,18) or (9,14). The probability of picking 5 from set n and 18 from set P is = 1/4 * 1/5.
The probability of picking 9 from set n and 14 from set P is = 1/4 * 1/5.

Hence Solution is : 2*(1/20)= 0.1
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Re: n is an integer chosen at random from the set {5, 7, 9, 11 } p is [#permalink]

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New post 22 Dec 2017, 09:12
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Re: n is an integer chosen at random from the set {5, 7, 9, 11 } p is   [#permalink] 22 Dec 2017, 09:12
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