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# N=P+Q+R, P, Q, R are consecutive positive integers. N=X*Y*Z,

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Manager
Joined: 13 Apr 2008
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N=P+Q+R, P, Q, R are consecutive positive integers. N=X*Y*Z, [#permalink]

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13 May 2008, 05:55
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N=P+Q+R, P, Q, R are consecutive positive integers. N=X*Y*Z, X, Y, Z, are positive consecutive integers.What is the remainder when N is divided by 5?
1) When P is divided by 5, the remainder is 1
2) When X is divided by 5, the remainder is 1

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Director
Joined: 10 Sep 2007
Posts: 933

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Re: DS-Consecutive Integers [#permalink]

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13 May 2008, 06:22
Say Q = P+1, R = P+2 (as they are consecutive integers)
=> N = 3P + 3
Say Y = X+1, R = X+2 (as they are consecutive integers)
=> N = X(X+1)(X+2)

Statement 1:
Tells us when P divided by 5 remainder is 1. That means P = 1, 6, 11, ....(remember all the numbers are +ve).
We will have N = 6, 21, 36....(Remainder 1 when divided by 5). So this statement is sufficient.

Statement 1:
Tells us when X divided by 5 remainder is 1. That means X = 1, 6, 11, ....(remember all the numbers are +ve).
We will have N = 6, 336, 1716....(Remainder 1 when divided by 5). So this statement is sufficient.

As both statements are sufficient, Answer D.

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Current Student
Joined: 28 Dec 2004
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Location: New York City
Schools: Wharton'11 HBS'12
Re: DS-Consecutive Integers [#permalink]

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13 May 2008, 11:32
yeah i too get D..

pick some numbers
P=1, or 6 or 11

u will always get 1 as remainder

x=1 6 or 11

u will always get 1 as remainder

Kudos [?]: 322 [0], given: 2

Re: DS-Consecutive Integers   [#permalink] 13 May 2008, 11:32
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# N=P+Q+R, P, Q, R are consecutive positive integers. N=X*Y*Z,

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