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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Hi Chetan, i have few doubts
1. how did you come to know that it will be a polygon (In the question it is give as standing on circle so why polygon )?
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Hi Chetan, i have few doubts
1. how did you come to know that it will be a polygon (In the question it is give as standing on circle so why polygon )?

Hi

If you draw a line between each adjoining pair, you will have a polygon equal to the number of people. This is just to visualize the pairs.
I have attached a figure for reference.
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ok i got it . one more question is that can it be polygon of more than 5 sides because it is mentioned n people ?
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abhinavsodha800
ok i got it . one more question is that can it be polygon of more than 5 sides because it is mentioned n people ?


It could be anything - 7, 700 anything
We get the value of n from nC2-n=28/2
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ANs : E
It is taking about pair of people. So 8 people, 4 pairs each, singing 2 mins each, 7 times.
#expertsreply
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Is it possible to get more questions of this type?
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Is there another approach to this question without polygons? I get the following:

Total time: 28 minutes
28/2 = 14 pairs singing
From that I would have done nC2 = 14... Which leads to nowhere. I still struggle to understand nC2 - n = 14. Geometry is not my strength.
How can I anchor the restriction here? "Not standing next to each other" You always have 2 people next....

Favorable outcome / all possible ourcomes...14 is my favourable outcome right? I am getting super confused here.

Also, as they stand on a circunference, should we take into account circular arrangement type of Permutation? (n-1)!? Instead con Combination?

Is this a quality question? Should I stick only to practicing only official questions?
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ruis
Is there another approach to this question without polygons? I get the following:

Total time: 28 minutes
28/2 = 14 pairs singing
From that I would have done nC2 = 14... Which leads to nowhere. I still struggle to understand nC2 - n = 14. Geometry is not my strength.
How can I anchor the restriction here? "Not standing next to each other" You always have 2 people next....

Favorable outcome / all possible ourcomes...14 is my favourable outcome right? I am getting super confused here.

Also, as they stand on a circunference, should we take into account circular arrangement type of Permutation? (n-1)!? Instead con Combination?

Is this a quality question? Should I stick only to practicing only official questions?
It took me a long time to understand that te restriction is -n. I got there by drawing difference scenarios. Still struggling with solvimg fast the green writing… I would just plug numbers and run

However I would have never been able to answer this qq under 2 mins. Would love to read other reasonings! Thank you everyone!!!

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ruis
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Is there another approach to this question without polygons? I get the following:

Total time: 28 minutes
28/2 = 14 pairs singing
From that I would have done nC2 = 14... Which leads to nowhere. I still struggle to understand nC2 - n = 14. Geometry is not my strength.
How can I anchor the restriction here? "Not standing next to each other" You always have 2 people next....

Favorable outcome / all possible ourcomes...14 is my favourable outcome right? I am getting super confused here.

Also, as they stand on a circunference, should we take into account circular arrangement type of Permutation? (n-1)!? Instead con Combination?

Is this a quality question? Should I stick only to practicing only official questions?
It took me a long time to understand that te restriction is -n. I got there by drawing difference scenarios. Still struggling with solvimg fast the green writing… I would just plug numbers and run

However I would have never been able to answer this qq under 2 mins. Would love to read other reasonings! Thank you everyone!!!

Posted from my mobile device


First recognize that the number of pairs without restriction is

N!/2!(N-2)! = N(N-1)/2

The restriction is no pairs of people next to each other.

So just imagine them in a line of, say, 4 people.

The first person is paired with the second, second with third and third with fourth.

How many pairs is that ?

4-1 = 3, which is N-1.

But, in a circle, the last person can also be paired with the first, so that's another pair, so the total disallowed pairs is:

N

Answering the question then becomes:

{[(N(N-1)/2]-N}*2 = 28, or:

N^2-3N-28 = 0.

This factors into:

(N-7)(N+4) = 0 and:

N=7



Visualizing polygons is completely unnecessary.
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