Given: n similar pumps, working together, fill the water tank T in two days. The amount of water, the tank T is capable to contain, is sufficient for 500 persons. Once T is full, pumps take break until the tank becomes empty. This cycle is repeated enough times in 1 month, to secure water for 1,500 persons.
Asked: If in the break of first cycle, after turning on the pumps for two days, half of the pumps become defective, how many days it takes after the first cycle so that all people have water?
The cycle is repeated equal to or more than 3 times in a month. (500*3 = 1500)
In 2 days, n pumps fill the tank T.
Thereafter, n/2 pumps will fill the tank T in 4 days.
(1) The duration of which a full reservoir becomes empty is 1 week.
First cycle takes takes 2+7 = 9 days
Second cycle takes = 4+7 = 11 days
Third cycle takes = 4+7 = 11 days
It will take 11+11 = 22 days after first cycle so that all people have water.
SUFFICIENT
(2) The pumps are turned on only for a specific time which is two days.
It is not mentioned in what time tank T becomes empty
It does not impact overall time since filling and emptying of pumps will still take same total time.
NOT SUFFICIENT
IMO A