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Nails and screws are manufactured at a uniform weight per nail and a

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paisaj87
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Nails and screws are manufactured at a uniform weight per nail and a [#permalink] New post   08 Feb 2016, 08:54
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Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 4 screws and 2 nails?

a. 4
b. 5/2
c. 2
d. 3/2
e. 5/4
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E
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Re: Nails and screws are manufactured at a uniform weight per nail and a [#permalink] New post   08 Feb 2016, 09:02
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paisaj87 wrote:
Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 4 screws and 2 nails?

a. 4
b. 5/2
c. 2
d. 3/2
e. 5/4


Hi,
let the weight of nail be n and that of screw be s..
so s+w=1/2 * (6s+1n)...
or 1n = 4s..

lets see the weight of 3 s and 3n= 3s+3*4s=15s..
and weight of 4s and 2n= 4s+2*4s=12s..
ratio= 15s/12s=15/12=5/4
E
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Re: Nails and screws are manufactured at a uniform weight per nail and a [#permalink] New post   19 May 2020, 09:17
paisaj87 wrote:
Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 4 screws and 2 nails?

a. 4
b. 5/2
c. 2
d. 3/2
e. 5/4


\(s + n = \frac{6s + n}{2}\)

So, \(2s + 2n = 6s + n\)

Or, \(n = 4s\)

Now, we have to find -

Quote:
The total weight of 3 screws, and 3 nails is how many times that of 4 screws and 2 nails?


Or, 3s + 3n = 3s + 3(4s) => 15s

And, 4s + 2n = 4s + 2(4d) => 12s

Hence required fraction is 15/12 = 5/4, Answer must be (E)
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Re: Nails and screws are manufactured at a uniform weight per nail and a [#permalink] New post   24 May 2020, 06:53
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paisaj87 wrote:
Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 4 screws and 2 nails?

a. 4
b. 5/2
c. 2
d. 3/2
e. 5/4


We can create the equation:

s + n = ½(6s + n)

2s + 2n = 6s + n

n = 4s

Since one nail weighs as much as 4 screws, we can express the total weight of 3 screws and 3 nails as 3s + 3n = 3s + 3(4s) = 15s and the total weight of 4 screws and 2 nails as 4s + 2n = 4s + 2(4s) = 12s. Therefore, the former total weight is 15s/12s = 5/4 of the latter total weight.

Answer: E
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Re: Nails and screws are manufactured at a uniform weight per nail and a [#permalink] New post   10 May 2023, 20:55
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Re: Nails and screws are manufactured at a uniform weight per nail and a [#permalink]
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