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sk88
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sk88
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I got 'B' and here is how..

Lets say there are 8 Red and y White

Quote:
If Joan takes 2 random marbles from the jar, is it more likely that she will have 2 red marbles than that she will have one marble of each color?

probability of 2 red marbles is
\(8/8+y * 7/7+y\) ---- (1)

probability of each marble of one color is
\(8/8+y * 7/7+y + y/8+y * 8/7+y\) ---- (2)

is (1) > (2)

translates to is y < 3.5

Stmt1 : NOTSUFF y<=8 donno if its les than 3.5
Stmt 2: Suff y> = 4 , yes its not less than 3.5
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sk88
sprtng
if y = 4,

so the probability of having two colors is 8*4/11*12
and probability of having two red is 8*7/11*12 clearly u have a bigger chance getting 2 reds

if y > 8 as is included in statement 2, then we can have y = 16

so the probability of having two colors is 8*15/24*23
while probability of having two red is 8*7/24*23 exactly opposite of when y = 4.

so statement 2 alone is not sufficient..

so is statement 1 because when y = 8, you have a bigger chance of getting two color than two reds while the other way around when y < 8.

i would go with E.


Yeah, E is what I put, but apparently it was wrong. I approached it almost the same way as you did. The right answer was B...

BTW, this was my 2nd question in the quant section MGMAT...it even said my 1st question was 600-700 level after i finished the test...I thought you start with a 500 level for the 1st question in each section???


that's because we missed one thing:

when you pick two red marbles, it doesn't really matter whether first is a red or first is white. but if we are picking two marbles of different color, then it matters as it is two cases, so that would be for the case y = 4, we have case of picking white first, 4/12*8/11, and then picking a red first, 8/12*4/11...so y>=4 is always sufficient...tricky tricky
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Yep that is tricky. Thanks for the exp



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