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kotela
I tried with various numbers it was giving Yes or No answers....but surprisingly the answer is C.........can anyone explain this please........

Here's the solution I came up with,

1 ..not sufficient cuz the expansion would never give us xy
2 ..same as 1

(x-y) squared= xsquare+ y square - 2xy = 8
x-y squared = xsquare + y Square - 2xy = 10 ,
becomes
-2xy= 8- xsquare-ysquare
-2xy = 10- xsquare - y square
solve simultaneously by adding both equations
-4xy = 18 -2xsquare - 2ysquare...divide both sides by -2
2xy = 9 + x square + y square
xy =(9+ x square + y square) divided by 2

We know x square + y square can not be negative. Thus, xy will always be greater than 0.

Ans . C
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onayemi
kotela
I tried with various numbers it was giving Yes or No answers....but surprisingly the answer is C.........can anyone explain this please........

Here's the solution I came up with,

1 ..not sufficient cuz the expansion would never give us xy
2 ..same as 1

(x-y) squared= xsquare+ y square - 2xy = 8
x-y squared = xsquare + y Square - 2xy = 10 ,
becomes
-2xy= 8- xsquare-ysquare
-2xy = 10- xsquare - y square
solve simultaneously by adding both equations
-4xy = 18 -2xsquare - 2ysquare...divide both sides by -2
2xy = 9 + x square + y square
xy =(9+ x square + y square) divided by 2

We know x square + y square can not be negative. Thus, xy will always be greater than 0.

Ans . C

But but X and Y can be negative -ve * -ve ==positive and (-x)^2 = +ve but here X can be -ve or +Ve and same is the case with Y..........Can you how you assumed X and Y to be positive...i agree that X^2 and Y^2 is positive but X and Y can be -Ve or +Ve .........Please correct me if i am wrong
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onayemi
kotela
I tried with various numbers it was giving Yes or No answers....but surprisingly the answer is C.........can anyone explain this please........

Here's the solution I came up with,

1 ..not sufficient cuz the expansion would never give us xy
2 ..same as 1

(x-y) squared= xsquare+ y square - 2xy = 8
x-y squared = xsquare + y Square - 2xy = 10 ,
becomes
-2xy= 8- xsquare-ysquare
-2xy = 10- xsquare - y square
solve simultaneously by adding both equations
-4xy = 18 -2xsquare - 2ysquare...divide both sides by -2
2xy = 9 + x square + y square
xy =(9+ x square + y square) divided by 2

We know x square + y square can not be negative. Thus, xy will always be greater than 0.

Ans . C
When you divided by -2 you forgot to divide 18 by -2 ... WINK WINK ! :)
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There is a problem with the question. The answer to the question posted, as is, would have to be E.....



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