Of the 645 speckled trout in a certain fishery that contains

Question

Of the 645 speckled trout in a certain fishery that contains only speckled and rainbow trout, the number of males is 45 more than twice the number of females. If the ratio of female speckled trout to male rainbow trout is 4:3 and the ratio of male rainbow trout to all trout is 3:20, how many female rainbow trout are there?

A. 192
B. 195
C. 200
D. 205
E. 208

How can I do this by setting up a Matrix? Please help.

A. 192 
B. 195 
C. 200 
D. 205 
E. 208

Monocle · Accepted Answer

Great question. You need to set it out in a table - it just makes it so much simpler to digest the information.

We are given 45 + 2F + F=645. We can then use the ratios to fill the rest of the table out from 2) onwards.

Answer = 205

Bunuel · Answer

{All} = {speckled} + {rainbow}

The ratio of male rainbow to all is 3x:20x:
20x = {speckled} + {female rainbow} + 3x

Since given that there are 645 speckled, then:
20x = 645 + {female rainbow} + 3x
{female rainbow} + 645 = 17x = {multiple of 17}

So, we have that {correct answer} + 645 = {multiple of 17}. Only option D works.

Answer: D.

grad_mba · Answer

I am doubtful about this line in the Q :

" ratio of male rainbow trout to all trout is 3:20 "

Does that mean Rm/645 = 3/20 ?  

In that case, by approxmation, Rm = 3 x 645 / 20 = 99

Now, Sf/Rm = 4/3 => Sf = 4 x 99 / 3 = 132 !

Dek · Answer

205.

It will be easier if you draw a table for this one. Let T be the total trout.

total speckled trout (ST) = 645
If female speckled trout = fST
then male speckled trout = 45 + 2fST
Therefore 45+ 2fST + fST = 645
We solve and get fST = 200
and mST= 445

Ratio of fST to mRT = 4:3
We have fST = 200
Solve ratio to get mRT = 150

Now ratio of mRT to T = 3:20
We have mRT = 150
Solve ratio to get T = 1000

Now unless youve drawn the table it might get a little complex.
From above we have mST and mRT
mST + mRT = 445 + 150 = 595
So T - 595 = total female trouts
1000 - 595 = 405 female trouts
We have from above that fST = 200

So (whew!) fRT = 405 - 200 = 205

tyagigar · Answer

question says total speclked = 645 and female speck to male speck = 4: 3 
so 7x = 645 = 92.14

so males speck = 3*92.14=276.42

what am i doing wrong ????

Bunuel · Answer

Stem says: the ratio of  female  speckled  trout  to  male  rainbow  trout  is 4:3.

kzivrev · Answer

Of the 645 speckled trout in a certain fishery that contains only speckled and rainbow trout, the number of males is 45 more than twice the number of females. If the ratio of female speckled trout to male rainbow trout is 4:3 and the ratio of male rainbow trout to all trout is 3:20, how many female rainbow trout are there?

A. 192
B. 195
C. 200
D. 205
E. 208

How can I do this by setting up a Matrix? Please help.

The first sentence contanes some amiguity in my eyes. I spent over and hour to figure out teh answer but went to totlay wrong direction taking the " the number of males is 45 more than twice the number of females" as a value for all the males in teh fishery and not for the Spackeled torut, having that done, I simply could not figure out cuz one variable was mising in my equations. but than when I looked at teh posts i see what I did wrong. otehrwise it is solvabale in 2 mints not hard at all, but I got stucked

Did anyone else experianced this kind of ambiguity issue
 Whats is teh source of the question.

MBAHopeful99 · Answer

Use a table set up as:

Gender Speckled Rainbow Total 
 Male   445 150 495
 
 Female    200  205  405

Total    645 355 1000

1. To find female speckled trout:
 45+2ST+ST = 645
 3ST=600
 ST = 200

2. Ratio of female speckled trout to male rainbow trout is 4:3
 4/3 = 200/x
 600=4x
 x=150

3. Ratio of male rainbow trout to all trout is 3:20
 3/20 = 150/x
 3000=3x
 x=1000

4. Fill in the blanks for total rainbow trout. 1000-645 = 355

5. Total rainbow trout - male rainbow trout. 355-150=205

Hope this helps

ENGRTOMBA2018 · Answer

Text in red : calculated values from the question.

Text in black: given information

Now per the question, total speckled trouts = 645 and out of these, the males are 45 more than twice the female speckled trouts

----> If female speckled trouts = x ---> male speckled trouts = 2x+45

Additionally, ratio of female speckled trouts (x) to male rainbow trouts = 4:3 ---> male rainbow trouts = 3x/4

Assume, number of female rainbow trouts = y ----> total rainbow trouts = male rainbow trouts + female rainbow trouts = 3x/4 + y

Finally, you have been given that the ratio of male rainbow trouts to total trouts = 3/20 ----> (3x/4) / total = 3/20

Thus, total = 5x

---> 2x+45+x= 645 ---> x = 200

and as 645+3x/4+y = 5x (susbtitute x = 200) to get y = 205. Thus D is the correct answer.

yezz · Answer

M spec = 445 and Female spec = 200

200/ Male rain = 4/3 , thus Male rainbow = 600/4 = 150 ( total male are thus 150+445 = 595)

150/t = 3/20 thus T = 1000 , thus total female = 1000-595 = 405

Total female = 200+ Female rainbow = 405 , thus Female rainbow = 205

mbaapp1234 · Answer

This problem is best done via an overlapping sets table.

We can set ST, RT, and Total as the first row column headers, and M/F/Total as the first column rows headers. Then we know that 2x+ 45 + x = 645, where x is the number of female speckled trout. Once we solve for that value, we can quickly plug it into the ratio 4:3 of female speckled trout to male rainbow trout to determine the number of male rainbow trout. However, this stage attempts to trick you, because 150 is an answer choice, but the question asks for the number of female speckled trout, so you have to then subtract 105 from 355, the total number of rainbow trout, to arrive at 205, the number of female rainbow trout.

nigina93 · Answer

a very confusing yet great question. lets go step by step. 
We know that total nu of sp is 645, out of which 2x+45 is male, while x is female. we get easy equation 2x+x+45=645 or x=200, so females of sp is 200, male of sp is 445. 
Then the question tells us that nu of f sp:m.r is 4:3. Since we have f.sp 200, we get a ration of 4/3=200/x or 150, so we have 150 of m.r
last ratio from stem tells us that m.r to total is 3/20. we know that m.r is 150, easy ratio we get is 150/x=3/20 or x is 1000, so in total of everything we have 1000.
lets sum up:
We have f.s 200,, m.s 445 total 645
We have f.r x, m.r. 150 total x
We have total of females 200+x m 595 and total 1000, 
from this table it is easy to identify number of f.r. which is 205

fskilnik · Answer

Excellent opportunity for the 'grid' (a.k.a double-matrix, table, you-name-it) and the 'k technique' (working together)!

https://preview.ibb.co/hdGEKU/07_Oct18_2w.gif

? = \left( {20k - 645} \right) - 3k

\left( {45 + 8k} \right) + 4k = 645\,\,\,\,\, \Rightarrow \,\,\,\,\,k = 50

? = \underleftrightarrow {\left( {1000 - 645} \right) - 150} = 205

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.

Gemmie · Answer

MS: Male Speckled
FS: Female Speckled
MR: Male Rainbow
FS: Female Rainbow

MS + FS = 645
MS = 45 + 2FS

FS : MR : All
4     3      20

FS   + MS        + FR      + MR = All = 20x
4x       8x +45     ?           3x

FS + MS = 645 
12x + 45 = 645
12x = 600 => x = 50

All = 100
==> FR + MR = 1000 - 645 = 355

MR = 3x = 150
FR = 355 - 150 = 205

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Of the 645 speckled trout in a certain fishery that contains

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