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Of the cans of peaches inspected yesterday at a certain plan

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Of the cans of peaches inspected yesterday at a certain plan  [#permalink]

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New post 23 Feb 2013, 03:00
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Of the cans of peaches inspected yesterday at a certain plant, 1.5 percent failed to pass inspection. Of the cans that failed inspection, 5/6 were incorrectly labeled and the rest were dented. If all of the cans that were incorrectly labeled or dented failed inspection, how many of the cans of peaches inspected yesterday at the plant were dented?

(1) 450 of the cans of peaches inspected yesterday at the plant failed to pass inspection.
(2) 29,550 of the cans of peaches inspected yesterday at the plant passed inspection.



Does 'If all of the cans that were incorrectly labeled or dented failed inspection' mean that F( failed) which is 1.5% of total cans = all the cans incorrectly labeled or dented ?

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Re: Of the cans of peaches inspected yesterday at a certain plan  [#permalink]

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New post 23 Feb 2013, 04:24
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Of the cans of peaches inspected yesterday at a certain plant, 1.5 percent failed to pass inspection. Of the cans that failed inspection,5/6 were incorrectly labeled and the rest were dented. If all of the cans that were incorrectly labeled or dented failed inspection, how many of the cans of peaches inspected yesterday at the plant were dented?
(1)450 of the cans of peaches inspected yesterday at the plant failed to pass inspection.
(2)29,550 of the cans of peaches inspected yesterday at the plant passed inspection.

Does 'If all of the cans that were incorrectly labeled or dented failed inspection' mean that F( failed) which is 1.5% of total cans = all the cans incorrectly labeled or dented ?

"If all of the cans that were incorrectly labeled or dented failed inspection" means that all the can that were either Incorrectly labelled or Dented were marked as FAILED

No of cans that FAILED = 1.5% of total cans = Cans that were Incorrectly labelled + Cans that were Dented

I hope this answers your query.

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Re: Of the cans of peaches inspected yesterday at a certain plan  [#permalink]

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New post 11 Jul 2013, 07:49
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x: total cans of peaches
0.015x: number of cans that failed inspection
0.015x*5/6: number of cans that wrong label
0.015x*1/6: number of cans that dented red

Since all the cans that were incorrectly labeled or dented red, there's no can that both incorrectly and dented red.

1. 450 of the cans of peaches inspected yesterday at the plant failed to pass inspection: number of cans that were dented red = 0.015x/6 = 450/6 = 75 => sufficient
2. 29,550 of the cans of peaches inspected yesterday at the plant passed inspection.
Total cans that passed inspection = 1 - 0.015x = 29,550 => x=30,000
Number of cans that were dented red = (0.015*30,000)/6 = 75 => sufficient
The answer is D
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Re: Of the cans of peaches inspected yesterday at a certain plan  [#permalink]

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New post 17 Aug 2019, 03:41
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Re: Of the cans of peaches inspected yesterday at a certain plan   [#permalink] 17 Aug 2019, 03:41
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