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# Of the total number of copies of Magazine X sold last week, 40 percent

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Of the total number of copies of Magazine X sold last week, 40 percent  [#permalink]

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03 Aug 2018, 10:42
00:00

Difficulty:

45% (medium)

Question Stats:

64% (01:06) correct 36% (00:55) wrong based on 56 sessions

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Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?

(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was$112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.

NEW question from GMAT® Quantitative Review 2019

(DS07206)

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Re: Of the total number of copies of Magazine X sold last week, 40 percent  [#permalink]

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03 Aug 2018, 12:02
To find X (the total number of copies).

Let p= number of magazines sold at full price

According to St 1:
1.5p = 112,500
p= 112,500/1.5
p= 75,000

In the question it is given that 40% of the total number of magazines were sold at full price. If "T" is the total number of magazines, then:
0.4T=75,000
T= 75,000/0.4
T= 187,500

Statement 1 is sufficient.

According to St 2:

p=75,000
In the question it is given that 40% of the total number of magazines were sold at full price. Hence,
0.4T = 75,000
T= 75,000/0.4
T= 187,500

Statement 2 is sufficient.

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Re: Of the total number of copies of Magazine X sold last week, 40 percent  [#permalink]

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04 Aug 2018, 01:03
Bunuel wrote:
Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?

(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was$112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.

NEW question from GMAT® Quantitative Review 2019

(DS07206)

Let 'c' be the total number of copies sold and k be the full price of each copy in dollar last week.
Given, number of copies sold at full price=40% of c=0.4c
So, 0.4c numbers of copies were sold at unit price k$. Question stem:- # of copies, c=? St1:- Last week, full price for a copy of Magazine X was$1.50 and the total revenue from full-price sales was $112,500. So, k=1.5$
Total revenue=no of copies sold at full price*unit price
Or, 112500=0.4c*k=0.4c*1.5
Or, $$c=\frac{112500}{0.6}=187500$$

Sufficient.

St2:- The total number of copies of Magazine X sold last week at full price was 75,000.
Or, 0.4c=75000
Or, $$c=\frac{75000}{0.4}=187500$$

Sufficient.

Ans. (D)
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Re: Of the total number of copies of Magazine X sold last week, 40 percent  [#permalink]

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04 Aug 2018, 23:22
Bunuel wrote:
Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?

(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was$112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.

NEW question from GMAT® Quantitative Review 2019

(DS07206)

To Find : The total number of copies of the magazine sold last week

(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was$112,500.

Let Full Price = f and The total number of copies of the magazine sold last week = T

f*1.5 =112500

0.4T = 112500/1.5

In DS we don't need to solve for, need to check if Statement 1 or 2 is suff

Hence Stat 1 is suff

(2) The total number of copies of Magazine X sold last week at full price was 75,000.

0.4T=75,000

We can find the value for T

Hence Stat 2 is suff

Hence D
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Re: Of the total number of copies of Magazine X sold last week, 40 percent &nbs [#permalink] 04 Aug 2018, 23:22
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