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Of the total number of copies of Magazine X sold last week, 40 percent

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Bunuel
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Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  03 Aug 2018, 10:42
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Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?


(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.


(DS07206)
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chichdefeater69
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  02 May 2020, 23:46
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abhiknag90 wrote:
To find X (the total number of copies).

Let p= number of magazines sold at full price

According to St 1:
1.5p = 112,500
p= 112,500/1.5
p= 75,000

In the question it is given that 40% of the total number of magazines were sold at full price. If "T" is the total number of magazines, then:
0.4T=75,000
T= 75,000/0.4
T= 187,500

Statement 1 is sufficient.

According to St 2:

p=75,000
In the question it is given that 40% of the total number of magazines were sold at full price. Hence,
0.4T = 75,000
T= 75,000/0.4
T= 187,500

Statement 2 is sufficient.

The answer is D.


I am using the online version and it looks like there is a typo.

Statement 2 reads: The total number of copies of Magazine X sold last week at full price was $75,000.

This $ sign completely threw me off and I am pretty sure is a mistake.
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abhiknag90
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  03 Aug 2018, 12:02
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To find X (the total number of copies).

Let p= number of magazines sold at full price

According to St 1:
1.5p = 112,500
p= 112,500/1.5
p= 75,000

In the question it is given that 40% of the total number of magazines were sold at full price. If "T" is the total number of magazines, then:
0.4T=75,000
T= 75,000/0.4
T= 187,500

Statement 1 is sufficient.

According to St 2:

p=75,000
In the question it is given that 40% of the total number of magazines were sold at full price. Hence,
0.4T = 75,000
T= 75,000/0.4
T= 187,500

Statement 2 is sufficient.

The answer is D.
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  04 Aug 2018, 01:03
1
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Bunuel wrote:
Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?


(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.


NEW question from GMAT® Quantitative Review 2019


(DS07206)


Let 'c' be the total number of copies sold and k be the full price of each copy in dollar last week.
Given, number of copies sold at full price=40% of c=0.4c
So, 0.4c numbers of copies were sold at unit price k$.
Question stem:- # of copies, c=?

St1:- Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.
So, k=1.5$
Total revenue=no of copies sold at full price*unit price
Or, 112500=0.4c*k=0.4c*1.5
Or, \(c=\frac{112500}{0.6}=187500\)

Sufficient.

St2:- The total number of copies of Magazine X sold last week at full price was 75,000.
Or, 0.4c=75000
Or, \(c=\frac{75000}{0.4}=187500\)

Sufficient.

Ans. (D)
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  04 Aug 2018, 23:22
Bunuel wrote:
Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?


(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.


NEW question from GMAT® Quantitative Review 2019


(DS07206)


To Find : The total number of copies of the magazine sold last week

(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.

Let Full Price = f and The total number of copies of the magazine sold last week = T

f*1.5 =112500

0.4T = 112500/1.5

In DS we don't need to solve for, need to check if Statement 1 or 2 is suff

Hence Stat 1 is suff

(2) The total number of copies of Magazine X sold last week at full price was 75,000.

0.4T=75,000

We can find the value for T

Hence Stat 2 is suff

Hence D
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  22 Oct 2018, 11:48
Bunuel wrote:
Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?


(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.


NEW question from GMAT® Quantitative Review 2019


(DS07206)



Statement 1)

Full price copy = 1.50 and the revenue from that is 112,500 from this we can find the number of full price copies.

Number of copies = revenue from full price/ cost per magazine full price.

Number of full price copies/total copies = \(\frac{40}{100}\)

Sufficient to find the total number of copies.

Statement 2)

75,000/total copies = \(\frac{40}{100}\)

Sufficient.

Answer choice D
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  31 Dec 2020, 15:33
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Bunuel wrote:
Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?


(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.


NEW question from GMAT® Quantitative Review 2019


(DS07206)


Total Magazine N, Full price=0.40N

(1) 0.40N*1.50=112,500; Sufficient.

(2) 75,000*0.40=Sufficient.

The answer is D.
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink] New post  06 Feb 2021, 22:08
Bunuel wrote:
Of the total number of copies of Magazine X sold last week, 40 percent were sold at full price. What was the total number of copies of the magazine sold last week?


(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500.

(2) The total number of copies of Magazine X sold last week at full price was 75,000.


NEW question from GMAT® Quantitative Review 2019


(DS07206)

1. Lets say \(M\) copies of the magazine were sold last week
2. 40% percent were sold at full price - meaning \(0.4M\) were sold at full price
3. We need the value of \(M\) to solve the question

(1) Last week, full price for a copy of Magazine X was $1.50 and the total revenue from full-price sales was $112,500 - Sufficient
a. Provides us the unit price for the Magazine i.e. \($1.50\)
b. Total revenue is given by \(0.4M * 1.50 = 112500\)
c. We have one equation and one variable and hence we can find the value of \(M\)

(2) The total number of copies of Magazine X sold last week at full price was 75,000 - Sufficient
a. We get the equation \(0.4M = 75000\)
b. We have one equation and one variable and hence we can find the value of \(M\)

Ans. D
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Re: Of the total number of copies of Magazine X sold last week, 40 percent [#permalink]
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