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# Ok, this one was in my kaplan math workbook, but there must

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Intern
Joined: 11 Jul 2009
Posts: 36
Ok, this one was in my kaplan math workbook, but there must [#permalink]

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14 Aug 2009, 09:04
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Ok, this one was in my kaplan math workbook, but there must be a misprint in the answers, because the answer to this one was omitted...

S is a set of positive integers such that if integer x is a member of S, then both $$x^2$$ and $$x^3$$ are also in S. If the only member of S that is neither the square nor the cube of another member of S is called the source integer, is 8 in S?

(1) 4 is in S and is not the source integer

(2) 64 is in S and is not the source integer

I think the answer is E...what does everyone else think?
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Manager
Joined: 25 Jul 2009
Posts: 116
Schools: NYU, NUS, ISB, DUKE, ROSS, DARDEN

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14 Aug 2009, 09:14
sk88 wrote:
Ok, this one was in my kaplan math workbook, but there must be a misprint in the answers, because the answer to this one was omitted...

S is a set of positive integers such that if integer x is a member of S, then both $$x^2$$ and $$x^3$$ are also in S. If the only member of S that is neither the square nor the cube of another member of S is called the source integer, is 8 in S?

(1) 4 is in S and is not the source integer

(2) 64 is in S and is not the source integer

I think the answer is E...what does everyone else think?

St1:
If 4 is in S and is not the source integer then 2 must be present in S => 2^3 = 8 must also be present in S.
=> SUFFICIENT

St2:
If 64 is in S and is not the source integer then it could either be due to 4 as a source integer or 2 as a source integer.
If 2 is the source integer then 8 is in S else its not.
=> NOT SUFFICIENT

ANS: A
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Manager
Joined: 07 Apr 2009
Posts: 145

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14 Aug 2009, 09:18
I guess the answer is 'A' and here is the reason:

Stmt 1 is SUFF: because if 4 is in S and is not source then it must be either a square/cube of a number and only 2^2 is 4 and no other way can we get 4 . So 2^3 = 8 exisits

Stmt 2: NOT SUFF
if 64 is not source, 64 can be 8^2 or 4^3 so 8 might exisits or not.
Manager
Joined: 12 Aug 2009
Posts: 102

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14 Aug 2009, 20:29
Echo - A is the answer.
Intern
Joined: 11 Jul 2009
Posts: 36

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14 Aug 2009, 22:06
Thanks everyone! That makes sense...I misread the stem and didn't understand what they meant by source integer - I thought they meant another separate integer (aside from the 3 mentioned) for some weird reason.
Re: Sets   [#permalink] 14 Aug 2009, 22:06
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