siddhantvarma
Let w: work to tile the hallway
work = rate*time => w = rate*time
From this we can find the individual rate of all three:
Olivia's rate (\(r_o\)) = w/6
Jacob's rate (\(r_j\)) = w/4
Ethan's rate (\(r_e\)) = w/5
For shortest time, we need the largest values of rate and for the longest time, we need the smallest values of rate. This is because time is inversely proportional to rate.
We know: 1/4 > 1/5 > 1/6
This means \(r_j\) > \(r_e\) > \(r_o\)
For shortest time, we need the largest values of rate so we'll take Jacob and Ethan.
w = (\(r_j\) + \(r_e\))*time => w = (w/4 + w/5)*t => t = 20/9 hours
Converting to minutes we get 2 hours 13 minutes.
For longest time, we need the smallest values of rate so we'll take Olivia and Ethan.
w = (\(r_o\) + \(r_e\))*time => w = (w/6 + w/5)*t => t = 30/11 hours
Converting to minutes we get 2 hours 47 minutes.
This is the correct solution.
Here is the official solution:The first thing to note is:
Jacob and Ethan working together will always be the fastest. This is because Jacob has the highest individual rate (1 hallway per 4 hours), and Ethan’s rate (1 hallway per 5 hours) is the second-highest (or in the middle).
Olivia and Ethan will always be the slowest. This is because Olivia has the lowest rate (1 hallway per 6 hours), and with Ethan’s second-highest rate, the combined speed is still slower compared to other pairs.
This is a Work problem. These questions are always solved by looking at the rate of work which is expressed per unit of time such as 1/4th of hallway per hour can be done by Jacob.
1. Rate of Work- Olivia's rate: She can complete the hallway in 6 hours, so her rate is 1 hallway per 6 hours.
- Jacob's rate: He can complete the hallway in 4 hours, so his rate is 1 hallway per 4 hours.
- Ethan's rate: He can complete the hallway in 5 hours, so his rate is 1 hallway per 5 hours.
2. Combined RatesWhen two people work together, their combined rate is the sum of their individual rates. The total time they take together to complete the hallway is calculated as:
Code:
Time = 1 / (combined rate)
A. Jacob and Ethan (Shortest Time)- Jacob's rate: 1 hallway per 4 hours
- Ethan's rate: 1 hallway per 5 hours
The combined rate for Jacob and Ethan is:
Code:
Combined rate = (1/4) + (1/5) = 9/20 of a hallway per hour
Time taken for Jacob and Ethan together:
Code:
Time = 1 / (9/20) = 20/9 ≈ 2.22 hours (or about 2 hours 13 minutes)
B. Olivia and Ethan (Longest Time)- Olivia's rate: 1 hallway per 6 hours
- Ethan's rate: 1 hallway per 5 hours
The combined rate for Olivia and Ethan is:
Code:
Combined rate = (1/6) + (1/5) = 11/30 of a hallway per hour
Time taken for Olivia and Ethan together:
Code:
Time = 1 / (11/30) = 30/11 ≈ 2.73 hours (or about 2 hours 44 minutes)