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On a 20 mile course, Pat bicycled at an average rate of 30

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On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post Updated on: 30 Dec 2012, 06:37
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On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162

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Originally posted by sananoor on 30 Dec 2012, 06:11.
Last edited by Bunuel on 30 Dec 2012, 06:37, edited 2 times in total.
Renamed the topic and edited the question.
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 30 Dec 2012, 06:44
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sananoor wrote:
On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162


At an average rate of 30 miles per hour in 12 minute (1/5 hours) Pat covers (distance) = (time) * (rate) = 1/5*30 = 6 miles, thus she should cover the remaining distance of 20 - 6 = 14 miles at an average rate of 8 miles per hour.

To cover 14 miles at an average rate of 8 miles per hour Pat needs (time) = (distance)/(rate) = 14/8 = 1.75 hours = 105 minutes.

Therefore Pat needs total of 12 + 105 = 117 minutes to cover the entire course.

Answer: C.
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Joined: 24 Jun 2012
Posts: 339
Location: Pakistan
Concentration: Strategy, International Business
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 30 Dec 2012, 07:11
i was doing absolutely right but was taking time in minutes rather than in hours...now a days i am so much worried about up coming gmat test that i am making a lot of mistakes...thanks a million
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Success isn't something that just happens - success is learned, success is practiced and then it is shared. -Sparky Anderson
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 08 Feb 2018, 10:56
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sananoor wrote:
On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162



Let's start with a WORD EQUATION

(Distance traveled at 30 mph) + (Distance traveled at 8 mph) = 20 miles

Distance = (rate)(time)
Let t = the time (in hours) Pat spent running at 8 mph
Aside: 12 minutes = 1/5 hours

So, we get: (30 miles per hour)(1/5 hours) + (8 miles per hour)(t hours) = 20 miles
Simplify: 6 + 8t = 20
So: 8t = 14
t = 14/8 = 7/4 = 1.75 hours = 105 minutes

How many minutes did Pat take to cover the entire course?
Pat spent 12 minutes riding a bike, and 105 minutes running
TOTAL time = 12 + 105 = 117

Answer: C

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Re: On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 12 Feb 2018, 17:40
sananoor wrote:
On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162


Pat originally biked 30 x 12/60 = 6 miles.

So it took him 14/8 = 7/4 = 1 3/4 = 1 hour and 45 minutes = 105 minutes to run the remaining 14 miles.

So, in total, Pat took 12 + 105 = 117 minutes to complete the course.

Answer: C
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Re: On a 20 mile course, Pat bicycled at an average rate of 30   [#permalink] 12 Feb 2018, 17:40
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On a 20 mile course, Pat bicycled at an average rate of 30

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