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On a scale that measures the intensity of a certain phenomen

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On a scale that measures the intensity of a certain phenomen [#permalink]

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On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?

(A) 5
(B) 50
(C) 10^5
(D) 5^10
(E) 8^10 - 3^10
[Reveal] Spoiler: OA

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Last edited by Bunuel on 07 Dec 2012, 06:35, edited 2 times in total.
Renamed the topic and edited the question.

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On a scale that measures the intensity of a certain phenomen [#permalink]

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kotela wrote:
Hey Guys i didn't understand the solution to the problem in OG 12 PS#98, can anyone please explain me the solution???


kotela it's better to post the question itself to get prompt replies. I guess you are talking about the following question:

On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
A. 5
B. 50
C. 10^5
D. 5^10
E. 8^10 - 3^10

Basically we are given that each number on the scale is 10 times the previous number. For example:
If reading of n=3 is 5 then the reading of n=4 would be 5*10 --> the reading of n=5 would be 5*10^2 --> the reading of n=6 would be 5*10^3. Therefore the reading of 8 will be 10^5 times as great as the reading of 3 (the power of 10 goes up by 1 for each step in reading and as there are 5 steps from 3 to 8 then the reading of 8 will be 10^5 times as great as the reading of 3).

Or think about it this way: we have functional relationship: when we increase the reading by 1 the intensity increases 10 times the previous one: \(f(n+1)=10*f(n)\).

So if \(f(3)=x\), then \(f(4)=10*f(3)=10x\) and so on. Therefore \(f(8)=10^5*f(3)\).

Answer: C.

Hope it's clear.
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Re: OG12 PS#98 [#permalink]

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New post 14 Jan 2012, 07:28
Bunuel wrote:
kotela wrote:
Hey Guys i didn't understand the solution to the problem in OG 12 PS#98, can anyone please explain me the solution???


kotela it's better to post the question itself to get prompt replies. I guess you are talking about the following question:

On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
A. 5
B. 50
C. 10^5
D. 5^10
E. 8^10 - 3^10

Basically we are given that each number on the scale is 10 times the previous number. For example:
If reading of n=3 is 5 then the reading of n=4 would be 5*10 --> the reading of n=5 would be 5*10^2 --> the reading of n=6 would be 3*10^3. Therefore the reading of 8 will be 10^5 times as great as the reading of 3 (the power of 10 goes up by 1 for each step in reading and as there are 5 steps from 3 to 8 then the reading of 8 will be 10^5 times as great as the reading of 3).

Or think about it this way: we have functional relationship: when we increase the reading by 1 the intensity increases 10 times the previous one: \(f(n+1)=10*f(n)\).

So if \(f(3)=x\), then \(f(4)=10*f(3)=10x\) and so on. Therefore \(f(8)=10^5*f(3)\).

Answer: C.

Hope it's clear.


Thanks a lot.....I will
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Re: maths problem [#permalink]

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As the intensity increases 10 times every time

from 3 to 8, it increases 5 times. So,answer is 10^5

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Re: maths problem [#permalink]

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New post 07 Jun 2012, 02:09
gnan wrote:
As the intensity increases 10 times every time

from 3 to 8, it increases 5 times. So,answer is 10^5



thanks a lot that was very helpful

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Re: Problem solving [#permalink]

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abusaleh wrote:
Can anyone give me proper explanation of this question?
On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
A) 5
B) 50
C) 10^5
D) 5^10
E) 8^10 - 3^10

Dear abusaleh,
This is a tricky question. It is based on logarithmic scales --- both the Richter scale for earthquakes and the decibel scale for the volume of sound follow this pattern.

It tell us if we we go from n to n+1 on the scale, the intensity is 10 times greater.

Start at 3. If we go from 3 to 4 on the scale, the intensity increases 10 times. Then from 4 to 5, it increases 10 times. Same, from 5 to 6, from 6 to 7, and from 7 to 8. There are five "steps" from 3 to 8, and each one of these steps increases the intensity by a factor of 10. That means, when we go from 3 to 8 on the scale, we multiply the intensity by 10 five times ---- 10*10*10*10*10 = 10^5

Answer = C

Does this make sense?

Mike :-)
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Re: Problem solving [#permalink]

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We know that:
\(f(n+1)=10f(n)\)

so \(f(8)=10f(7)\) , \(f(7)=10f(6)\) and so on...

\(f(8)=10*10*10*10*10f(3)\)

Each 10 represents a "step back"
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A soln. easy to understand-

For n=3, consider the intensity to be x.

For n+1 = 4 , we have [intensity*10 ]= 10x
For n+2 = 5 , we have [10x*10 ]= 100x
For n+3 = 6 , we have [100x*10 ]= 1000x
For n+4 = 7 , we have [1000x*10 ]= 10000x
For n+5 = 8 , we have [10000x*10 ]= 100000x

Now , for n = 8 -->100000x = 10^5 x
which is 10^5 times x, the original intensity at n=3

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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mydreammba wrote:
On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?

(A) 5
(B) 50
(C) 10^5
(D) 5^10
(E) 8^10 - 3^10

n = 10^(n-1)*k , where n=1,2,3,.......
8 = 10^7*k
3 = 10^2*k
It implies 8 is 10^5 times of 3

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 28 Feb 2016, 11:27
mydreammba wrote:
On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?

(A) 5
(B) 50
(C) 10^5
(D) 5^10
(E) 8^10 - 3^10


According to Manhattan-Gmat, the GMAT is a test of foreign language.
Any reading is 10 times the previous reading, if the reading is increasing by 1.

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 30 Apr 2016, 23:04
Hello all, I was wondering why we can't solve for n.
If n +1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n wouldn't that mean n + 1 = 10 * n?

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 02 May 2016, 03:25
investdave wrote:
Hello all, I was wondering why we can't solve for n.
If n +1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n wouldn't that mean n + 1 = 10 * n?


Please read the following posts:
on-a-scale-that-measures-the-intensity-of-a-certain-phenomen-126082.html#p1029066
on-a-scale-that-measures-the-intensity-of-a-certain-phenomen-126082.html#p1195384
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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 02 May 2016, 07:18
mydreammba wrote:
On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?

(A) 5
(B) 50
(C) 10^5
(D) 5^10
(E) 8^10 - 3^10


To solve this problem we need to examine the information in the first sentence. We are told that “a reading of n + 1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n.”

Let’s practice this idea with some real numbers. Let’s say n is 2. This means that n + 1 = 3. With the information we were given we can say that a reading of 3 is ten times as great as the intensity of a reading of 2.

Furthermore, we can say that a reading of 4 is actually 10 x 10 = 10^2 times as great as the intensity of a reading of 2.

Increasing one more unit, we can say that a reading of 5 is 10 x 10 x 10 = 10^3 times as great as the intensity of a reading of 2.

We have found a pattern, which can be applied to the problem presented in the stem:

3 is “one” unit away from 2, and thus a reading of 3 is 10^1 times as great as the intensity of a reading of 2.

4 is “two” units away from 2, and thus a reading of 4 is 10^2 times as great as the intensity of a reading of 2.

5 is “three” units away from 2, and thus a reading of 5 is 10^3 times as great as the intensity of a measure of 2.

We can use this pattern to easily answer the question. Here we are being asked for the number of times the intensity corresponding to a reading of 8 is as great as the intensity corresponding to a reading of 3. Because 8 is 5 units greater than 3, a reading of 8 is 10^5 times as great as the intensity corresponding to a reading of 3.

Answer C.
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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 20 Mar 2017, 07:17
From question

n+1 = N * 10

say the readings are 1,10,100,1000,10^4,10^5 so on... Implies it is 5 times greater
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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 21 Mar 2017, 04:12
mydreammba wrote:
On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?

(A) 5
(B) 50
(C) 10^5
(D) 5^10
(E) 8^10 - 3^10



we can say that f(n) = 10^n
f(8)/ f(3) = 10^8/10^3 = 10^5

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 03 Apr 2017, 00:05
The intensity of 3 is n.
8-3= 5

Therefore the intensity of 8 will be 5 times the intensity of 3.
Therefore the answer is 10^5.
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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 04 Aug 2017, 10:25
Bunuel wrote:
kotela wrote:
Hey Guys i didn't understand the solution to the problem in OG 12 PS#98, can anyone please explain me the solution???


kotela it's better to post the question itself to get prompt replies. I guess you are talking about the following question:

On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
A. 5
B. 50
C. 10^5
D. 5^10
E. 8^10 - 3^10

Basically we are given that each number on the scale is 10 times the previous number. For example:
If reading of n=3 is 5 then the reading of n=4 would be 5*10 --> the reading of n=5 would be 5*10^2 --> the reading of n=6 would be 3*10^3. Therefore the reading of 8 will be 10^5 times as great as the reading of 3 (the power of 10 goes up by 1 for each step in reading and as there are 5 steps from 3 to 8 then the reading of 8 will be 10^5 times as great as the reading of 3).

Or think about it this way: we have functional relationship: when we increase the reading by 1 the intensity increases 10 times the previous one: \(f(n+1)=10*f(n)\).

So if \(f(3)=x\), then \(f(4)=10*f(3)=10x\) and so on. Therefore \(f(8)=10^5*f(3)\).

Answer: C.

Hope it's clear.


I believe the highlighted part should be 10 * (5 *10^2) = 5 * 10^3

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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New post 05 Aug 2017, 00:12
warriorguy wrote:
Bunuel wrote:
kotela wrote:
Hey Guys i didn't understand the solution to the problem in OG 12 PS#98, can anyone please explain me the solution???


kotela it's better to post the question itself to get prompt replies. I guess you are talking about the following question:

On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
A. 5
B. 50
C. 10^5
D. 5^10
E. 8^10 - 3^10

Basically we are given that each number on the scale is 10 times the previous number. For example:
If reading of n=3 is 5 then the reading of n=4 would be 5*10 --> the reading of n=5 would be 5*10^2 --> the reading of n=6 would be 3*10^3. Therefore the reading of 8 will be 10^5 times as great as the reading of 3 (the power of 10 goes up by 1 for each step in reading and as there are 5 steps from 3 to 8 then the reading of 8 will be 10^5 times as great as the reading of 3).

Or think about it this way: we have functional relationship: when we increase the reading by 1 the intensity increases 10 times the previous one: \(f(n+1)=10*f(n)\).

So if \(f(3)=x\), then \(f(4)=10*f(3)=10x\) and so on. Therefore \(f(8)=10^5*f(3)\).

Answer: C.

Hope it's clear.


I believe the highlighted part should be 10 * (5 *10^2) = 5 * 10^3

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Re: On a scale that measures the intensity of a certain phenomen [#permalink]

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what level question is this?

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Re: On a scale that measures the intensity of a certain phenomen   [#permalink] 25 Aug 2017, 00:16

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