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kevincan
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I also agree with u2lover...

E

st1
only gives us the max number of member in the club

st2
gives that range of the percentage...
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sharadGmat
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acfuture
I also agree with u2lover...

E

st1
only gives us the max number of member in the club

st2
gives that range of the percentage...



E it is.. My original answer was wrong..
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get E too. Hope theres isnt catch anywhere.

how much time did you guys take to solve this ?
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acfuture
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shahnandan,

how crowded is Germany due to the World Cup?
Sorry that Germany lost... talk about expect the unexpected...
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MA
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kevincan
On January 1 of this year, n% of the members of a tennis club smoked. Since then, however, one of every three smokers managed to stop smoking, while 10% of those who did not smoke on January 1 now do so. Currently, d% of the members smoke. Is d =n ?

(1) The club has fewer than 300 members
(2) 20<n< 25


E

your questions are similar to the challange questions.
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I am getting (E). The condition can be written as an equation that depends only on d and n, and by solving for d=n we get the onle answe: ~ 23.1. Since it is inside the range 20<n<25 it proves that we can have it both ways: d=n and d !=n. So, (E)
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Can anyone show that (1) is also sufficient?
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ps_dahiya
v1rok
I am getting (E). The condition can be written as an equation that depends only on d and n, and by solving for d=n we get the onle answe: ~ 23.1. Since it is inside the range 20<n<25 it proves that we can have it both ways: d=n and d !=n. So, (E)

Exactly the same thinking.



I am missing something in the question.. N being eqaul to D isn't dependent on number of memebers of the club at all.. So how can statement 1 even provide any data to help prove/disprove N=D ?

d= (2n/3)+(100-n)/10

so, if n=d, then

(2n/3)+10-n/10=n
==> n =300/11.

So n=d, only when n=300/11. Statement 2 tells us that n can't be this value. So SUFF..

What am I getting wrong here ?
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sharadGmat
ps_dahiya
v1rok
I am getting (E). The condition can be written as an equation that depends only on d and n, and by solving for d=n we get the onle answe: ~ 23.1. Since it is inside the range 20<n<25 it proves that we can have it both ways: d=n and d !=n. So, (E)

Exactly the same thinking.


I am missing something in the question.. N being eqaul to D isn't dependent on number of memebers of the club at all.. So how can statement 1 even provide any data to help prove/disprove N=D ?

d= (2n/3)+(100-n)/10

so, if n=d, then

(2n/3)+10-n/10=n
==> n =300/11.

So n=d, only when n=300/11. Statement 2 tells us that n can't be this value. So SUFF..

What am I getting wrong here ?


First of all you agree that st1 is INSUFF.

Now lets go to statement 2.
Stem is d= (2n/3)+(100-n)/10

Using this stem and st2 (20<n< 25) can you tell Is d=n? may be d = n or may not be. Stem could be satisfied with many values of d and n where n is between 20 and 25. Thats why its INSUFF.

Don't put d = n. This is asked. Some times what we do is what is being asked, we use that to answer the question.

Hope this helps.
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First of all for p=n , n must be 300/13, in other words, exactly 3/13 of the members must have been smokers at the beginning of the year. But the number of smokers must also be divisible by 10,3 and 13 (i.e by 390). Since there are fewer than 300 members, this is impossible
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First of all for p=n , n must be 300/13, in other words, exactly 3/13 of the members must have been smokers at the beginning of the year. But the number of smokers must also be divisible by 10,3 and 13 (i.e by 390). Since there are fewer than 300 members, this is impossible.

(1) is sufficient
(2) is not since 300/13 satisfies this inequality

OA: A



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